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taurus [48]
3 years ago
5

Good mental health is the ability to __________.A.express feelings appropriatelyB.allow daily situations to cause excessive anxi

etyC.recognize and cope with the daily demands of lifeD.none of the above
Biology
2 answers:
USPshnik [31]3 years ago
8 0

Answer: Option C. Recognize and cope with the daily demands of life.

Explanation:

Good mental health recognizes and copes with the daily demands of life. Mental health is a state of well-being in which an individual recognizes his or her own proficiency, can cope with the normal stresses of life, can work productively and is able to make a contribution to his or her community. Mental health is important to our collective and individual ability as humans to think, interact with each other, earn a living and enjoy life. Mental health promotion, protection, and restoration should be considered as an important concern for individuals, communities, and societies.

attashe74 [19]3 years ago
8 0

Answer: Option C recognize and cope with the daily demands of life

Explanation: Good mental health is the ability to deal with stress daily and to fulfill one's goals and ambition. Good mental health is the how capable you are in dealing with trauma, anxiety as well as negative and positive feelings. Good mental health helps us to be able to relate properly with people.

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2. Dominant trait: cleft chin (C) Mother’s gametes: Cc
andre [41]

.2. Offspring Genotypes will be Cc or cc.

     Offspring phenotypes : Cleft chin or no cleft chin.

    % chance child will have cleft chin: 50%

3.  % chance child will have arched feet: 25%

4.  % chance child will have blonde hair:  50%

5.  % chance child will have normal vision: 25%

 

Explanation:

CASE 1 :

 Dominant trait: cleft chin (C)

    Recessive trait: lacks cleft chin (c)

    Father’s gametes: cc

    Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and  c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents=  \frac{1}{2}C + \frac{1}{2} c........(i)

Gametes of cc parents =<u> </u>\frac{1}{2}c + \frac{1}{2}c .........(ii)

Combining (i) and (ii) we get,

\frac{1}{2}  Cc + \frac{1}{2} cc                              

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin  =\frac{0.5}{1} ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous   (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

     A from mother, a from father =Aa

     a from mother, A from Father = Aa

     a from mother, a from father = aa

Gametes of Aa parent =\frac{1}{2} A + \frac{1}{2} a

Gametes of other Aa parent = \frac{1}{2} A + \frac{1}{2} a

                                       <u>..................................................................................</u>

                                              \frac{1}{4} AA + \frac{1}{4} Aa

                                                                           +  \frac{1}{4} Aa +\frac{1}{4} aa

                                   <u>..........................................................................................</u>

                                <u>\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa</u>

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = \frac{0.25}{1} × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive  (bb)

Father’s gametes: Heterozygous  (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in  half  Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous  (Ff)

Father’s gametes: Heterozygous  (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF  then phenotype farsightedness

Genotype Ff then phenotype  farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

 

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3 years ago
Umm yeah I’m doing old work anybody wanna help
Andrei [34K]
I believe is A I’ve learned that in 8th grade I think
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An albino man marries a normally-pigmented woman who had an albino mother. What is the probability that they will have pigmented
tangare [24]

Answer:

its about %5 more than it usualy is with is 1%

Explanation:

do the math if you dont belives me br

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2 years ago
Which of the following parts of an atom have almost the same mass
MariettaO [177]

Answer:

protons and electrons

4 0
2 years ago
What is active transport
Gelneren [198K]
The movement of ions across the cell of a membrane of higher regions of concentration.
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