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3 years ago

Can someone please help me with #22 I would appreciate it. Thanks

Biology

1 answer:

igor_vitrenko [27]3 years ago

7 0

Answer:

Glycolysis occurs in the Cytoplasm

Electron Transport Chain occurs in the Mitchondria

Krebs Cycle also occurs in the mitchondria

Explanation:

Glycolysis is the first step in the breakdown of glucose to extract energy for cellular metabolism. Nearly all living organisms carry out glycolysis as part of their metabolism. The process does not use oxygen and is therefore anaerobic. Glycolysis takes place in the cytoplasm of both prokaryotic and eukaryotic cells.

The electron transport chain is the last stage of the respiration pathway. It is the stage that produces the most ATP molecules. The electron transport chain is a collection of carrier proteins found on the inner membrane of mitochondria. NADH hydrogen ions and electrons into the transport chain.

The Krebs cycle happens only within the mitochondrial matrix. Pyruvate is formed in the cytosol of the cell, then imported into the mitochondria.

(Credits to websites)

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Answer:

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Explanation:

As we know weight of 113 In isotope is equal to the sum of product of fraction-of-occurrences of two constituents isotopes and their atomic weight

$^{115}In_w = f_{113}*A_{113} + f_{115}*A_{115}$ ------(1)

As we know sum of fraction-of-occurrences of two constituents isotopes is equal to one.

$f_{113} + f_{115} = 1\\f_{113} = 1- f_{115}$ ---------(2)

Substituting the given values in equation 1, we get

$^{115}In_w = f_{113}*A_{113} + f_{115}*A_{115}\\114.818 = (1 - f_{115}) * 112.904 + f_{115} * 114.904\\f_{115} = 0.957$

Substituting this value in equation 2 we get -

$f_{113} = 1- f_{115}\\f_{113} = 1- 0.957 \\f_{113} = 0.043$

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