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3 years ago

Can anyone help. I will give you a thanks for the help

Mathematics

2 answers:

Sever21 [200]3 years ago

8 0

A in casual is a long vowel and the e in meteor is long too so all of them are long I

Lina20 [59]3 years ago

3 0

Im pretty sure casual is fluid

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The floor of our classroom is 50 feet by 75 feet. What is the area of our floor?

N76 [4]

3750
Area of rectangle= length * hight

8 0

4 years ago

3x-8=10 Answer it correctly

shepuryov [24]

Answer:

x=6

Step-by-step explanation:

3x-8=10

+8 +8

3x=18

x=18/3

x=6

3 0

4 years ago

Read 2 more answers

Complete the equation of the line through (-9,-9) and (-6,0)

Rudik [331]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis.

According to the data of the statement we have the following points:

$(x_ {1}, y_ {1}): (- 9, -9)\\(x_ {2}, y_ {2}): (- 6,0)$

We found the slope:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0 - (- 9)} {- 6 - (- 9)} = \frac { 9} {- 6 + 9} = \frac {9} {3} = 3$

Thus, the equation is of the form:

$y = 3x + b$

We substitute one of the points and find b:

$0 = 3 (-6) + b\\0 = -18 + b\\b = 18$

Finally, the equation is:

$y = 3x + 18$

Answer:

$y = 3x + 18$

7 0

4 years ago

The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain riv

Gelneren [198K]

Answer:

$v_2 \approx 1.12246\ m.s^{-1}$

$v_{10}\approx 1.4678\ m.s^{-1}$

$v_{100}\approx 1.4678\ m.s^{-1}$

Step-by-step explanation:

Mass of particles that a river can transport, $m\propto\ v^6$

where:

v = velocity of river flow

When $v=1\ m.s$

then the mass transported, $m \propto 1^6$

When mass is twice:

$v=\sqrt[6]{2}$

$v_2 \approx 1.12246\ m.s^{-1}$

When mass is 10 times:

$v=\sqrt[6]{10}$

$v_{10}\approx 1.4678\ m.s^{-1}$

When mass is 100 times:

$v=\sqrt[6]{100}$

$v_{100}\approx 1.4678\ m.s^{-1}$

7 0

3 years ago

The perimeter of a rectangle is 42 meters. The length of the rectangle is 3 meters less than twice the width. Find the length of

NNADVOKAT [17]

Answer:

The length of the rectangle is 13m

5 0

3 years ago