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luda_lava [24]
3 years ago
5

123 120 27 any links will be reported

Mathematics
1 answer:
neonofarm [45]3 years ago
6 0

Answer:

were is the pic!

Step-by-step explanation:

You might be interested in
PICTURE INCLUDED<br><br>whats the length of the line?<br><br>A. 9<br>B. 8 <br>C. √45<br>D. √27 ​
Fynjy0 [20]

Answer:

C

Step-by-step explanation:

Formula:

d = √(x2−x1)^2 + (y2−y1)^2

plug in

d = √(8−2)^2 + (5−2)^2

d = √(6)^2 + (3)^2

d = √36 + 9

d = √45

4 0
3 years ago
How much water conditioner for 2.5 gallon tank?
vivado [14]
If i'm correct you should add 0.5 mL to your 1 gallon tank, and I would say about 1.25 mL to your 2.5 gallon. It will not be extreme if you end up putting a little more in than you are supposed to. I'm not 100% because i haven't slept so my brain is being slow.
8 0
3 years ago
Suppose there are two cubes, with the first cube having a side of h, and the second cube having a side of 5h. What is the relati
nikdorinn [45]
The answer is 0.008a^3 because you would do 0.2 to the power of 3
4 0
3 years ago
In ΔLMN, \overline{LN}
Karolina [17]

Answer:

\bold{\angle NLM = 10^\circ}

Step-by-step explanation:

Given a ΔLMN.

Line LN is extended to point O.

such that:

\text{m}\angle MNO = (5x-13)^{\circ}

\text{m}\angle NLM = (x-4)^{\circ} and

\text{m}\angle LMN = (2x+19)^{\circ}

To find:

\text{m}\angle NLM=?

Solution:

Kindly refer to the attached image for the given triangle and dimensions of angles.

Let us recall the external angle property of a triangle:

The external angle of a triangle is equal to the sum of two opposite internal angles.

i.e.

\angle MNO = \angle NLM + \angle LMN\\\Rightarrow 5x-13 = x-4+2x+19\\\Rightarrow 5x-13 = 3x+15\\\Rightarrow 5x-3x = 13+15\\\Rightarrow 2x=28\\\Rightarrow x =14

Putting the value of x in \angle NLM.

\angle NLM=14-4 \\\Rightarrow \bold{\angle NLM = 10^\circ}

5 0
3 years ago
PLEASE HELPPP<br><br> Which expression is equivalent to
Anettt [7]

Answer:

Fourth option

Step-by-step explanation:

Given the expression in the picture:

Apply Power of Power Rule

\frac{64g {}^{9} h {}^{6}k {}^{12}  }{8g {}^{3} h {}^{2} }

8g {}^{6} h {}^{4} k {}^{12}

The left side of the equation option had this in the fourth option so the fourth option is right

7 0
3 years ago
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