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Lana71 [14]
3 years ago
13

A store manager paid $95 for an item and set the selling price at $116.85. What was the percent markup?

Mathematics
1 answer:
Neporo4naja [7]3 years ago
6 0

We have been given that a store manager paid $95 for an item and set the selling price at $116.85. We are asked to find the percent mark-up.

We will use percent increase formula to solve our given problem.  

\text{Percent increase}=\frac{\text{Final}-\text{Initial}}{\text{Initial}}\times 100\%

\text{Percent increase}=\frac{\$116.85-\$95}{\$95}\times 100\%

\text{Percent increase}=\frac{\$21.85}{\$95}\times 100\%

\text{Percent increase}=0.23\times 100\%

\text{Percent increase}=23\%

Therefore, the mark-up will be 23% and option 'b' is the correct choice.

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Which of the following equations is equivalent to 2/3 x - 1/2 y = 6? 2x - y = 6 2x - y = 36 4x - 3y = 36
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Answer: THE LAST OPTION

Step-by-step explanation:

1. You have the following equation given in the problem:

\frac{2}{3}x-\frac{1}{2}y=6

2. If you multiply both sides of the equation shown above by 6, you obtain the following:

\frac{2*6}{3}x-\frac{1*6}{2}y=6*6

\frac{12}{3}x-\frac{6}{2}y=36

3. When you simplify the equation, you obtain the following equivalent equation:

4x-3y=36

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What is the length of a missing side of a 48 feet and 52 feet 90° triangle
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Step-by-step explanation:

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What is the lowest term of 75/60 as an improper fraction?
Katena32 [7]
75/60 = 15/12 = 5/4. This is the lowest term
5 0
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Read 2 more answers
part 3. Find the coordinates of the vertices of the triangle after a reflection across the y-axis and then across the line y= 2.
garik1379 [7]

Answer:

  c.  S'(3, 1), T'(1, -1), U'(0, 1)

Step-by-step explanation:

Reflection across the y-axis negates the x-coordinate, so is equivalent to the transformation ...

  (x, y) ⇒ (-x, y)

Reflection across the horizontal line y=c is equivalent to the transformation ...

  (x, y) ⇒ (x, 2c-y)

So, the combined reflections are equivalent to the transformation ...

  (x, y) ⇒ (-x, 4 -y)

Then we have ...

  S(-3, 3) ⇒ S'(-(-3), 4-3) = S'(3, 1)

  T(-1, 5) ⇒ T'(-(-1), 4-5) = T'(1, -1)

  U(0, 3) ⇒ U'(-(0), 4-3) = U'(0, 1) . . . . matches choice C

7 0
3 years ago
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