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lara31 [8.8K]
2 years ago
7

Miguel and Grace started collecting rare coins at the same time. Back then, they had the same number of rare coins. Miguel has b

een collecting 5 coins each week and he now has 38 coins. Grace has been collecting 3 coins each week and she now has 24 coins. How many rare coins did they have all together when they started collecting?
A) 3
B) 6
C) 7
D) 14
Mathematics
1 answer:
Volgvan2 years ago
6 0

Answer:

Miguel and Grace have collected 7 coins each week.

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Evaluate the expression 23[1/4 +4(36÷12)]​
Katyanochek1 [597]
<h2>281.75</h2>

Step-by-step explanation:

23 [1/4 +4(36÷12)]

23 [1/4 +4×3]

23 [0.25 +12]

23 ×12.25

281.75

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4 0
3 years ago
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Serga [27]

Answer:

x=0 and y=5

Step-by-step explanation:

8x-25+2x=-25

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Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
If x = 2 and y = -3, what is the value of 2x^2 + 3xy – 2y^2?
sammy [17]

Answer: Given as,X=2 & Y=3,

now multiplying we get,

2xxy=2×2×3=12

Ans.) 12

Step-by-step explanation:

7 0
2 years ago
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Answer ya so  1 is the answer

Step-by-step explanation:

5 0
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