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3 years ago

What is the missing constant term in the perfect square that starts with x^2 - 20x

Mathematics

2 answers:

Andre45 [30]3 years ago

4 0

Answer:

100

Step-by-step explanation:

To make a perfect square trinomial, you want to divide the use the following equation to find the missing constant:

$(\frac{b}{2} )^{2}$ when the quadratic is in standard form.

In this case, we would divide -20 by 2 and square it

-20/2 = -10

(-10)^2 = 100

Leviafan [203]3 years ago

4 0

(a - b)² = a² - 2ab + b²

- 2ab = 20x

- ab = 10x } => b = - 10

a = x

(x - 10)² = x² - 20x + 100

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Can I have help with the question

sleet_krkn [62]

Answer:

Midpoint = (3.5, 4.5)

Perpendicular bisector = y = $\frac{7}{9}$ x + $\frac{16}{9}$

Step-by-step explanation:

[] We can solve this using the midpoint formula:

-> See attached

[] Plug-in our coordinates and solve:

$(\frac{7+0}{2} ,\frac{0+9}{2} )=(\frac{7}{2} ,\frac{9}{2} )=(3.5,4.5 )$

[] Now we will find the slope to solve for the perpendicular bisector.

-> We will use slope-intercept form, see attached

$\frac{9-0}{0-7}=\frac{9}{-7}$

-> The slopes of two perpendicular lines are negative reciprocals of each other, so $\frac{7}{9}$ will be the slope of or perpendicular bisector

-> Now we can solve for the equation by using y – y1 = m ( x – x1), were y1 and x1 are the coordinates of our midpoint

y - 4.5 = $\frac{7}{9}$ (x-3.5)

y - 4.5 = $\frac{7}{9}$ x- $\frac{49}{18}$

y = $\frac{7}{9}$ x- $\frac{49}{18}$ + 4.5

y = $\frac{7}{9}$ x + $\frac{16}{9}$

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

6 0

2 years ago

Find the surface area of a sphere<br> Show all the work

IrinaVladis [17]

Answer:

452cm2

Step-by-step explanation:

surface area of sphere =4πr2

so 4π62 which equals to 452.39.

hope this helps u understand:)

5 0

2 years ago

Finding the Median from a Dot Plot

MAXImum [283]

Answer:

median rainfall for highland storms = 18mm

median rainfall for lowland storms = 18mm

median rainfall for lowland storms = 17mm if the list of numbers is

2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32

Step-by-step explanation:

The median is the middle number of a sequence of ordered numbers.

The formula for the median is:

median = (n + 1 )/ 2

where n = total number of values

Note: the number that you find with this formula is the position. SO you have to go to the sequence of numbers and find the number that lies in that position.

Highland storms:

4 6 8 10 12 14 16 18 20 22 24 26 28 30 32

The numbers are already in ascending order so we can proceed.

n = 15

∴ median = (15+1)/2

= 16/2

= 8

The median is the umber in the 8th position

so, the median rainfall for highland storms is 18mm

Lowland storms:

4 6 8 10 12 14 16 18 20 22 24 26 28 30 32

The numbers are already in ascending order so we can proceed.

n = 15

∴ median = (15+1)/2

= 16/2

= 8

The median is the number in the 8th position.

∴ median rainfall for lowland storms is = 18mm

<u>Unclear: if this is the list of numbers: </u>

2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32

then the median would be:

n = 16

median = (16+1)/2

= 17/2

= 8.5

This means the median lies between the numbers in the 8th and 9th position.

∴ The median is = (16 + 18)/2

= 34/2

= 17

5 0

3 years ago

Read 2 more answers

In the standard (x, y) coordinate plane, if the x-coordinate of each point is 2 times the y-coordinate, what is the slope of the

uranmaximum [27]

1/2 (Rise over Run)
I hope this helps out :3

3 0

3 years ago

2x + y = 15 x + y = 10

Artyom0805 [142]

Answer:

2x+y=15x+y=10

Consider the first equation. Subtract 15x from both sides.

2x+y−15x=y

Combine 2x and −15x to get −13x.

−13x+y=y

Subtract y from both sides.

−13x+y−y=0

Combine y and −y to get 0.

−13x=0

Divide both sides by −13. Zero divided by any non-zero number gives zero.

x=0

Consider the second equation. Insert the known values of variables into the equation.

15×0+y=10

Multiply 15 and 0 to get 0.

0+y=10

Anything plus zero gives itself.

3 0

2 years ago