Word form:
Two and seven hundred eighty-nine thousandths
Expanded form:
2
+ 0.7
+ 0.08
+ 0.009
9= 9,000,000/ nine million
9= 900,000/ nine hundred thousand
0= since there's no value we leave it out.
5= 5000/ five thousand
4= 400/ four hundred
8= 80/ eighty
2= 2/two
So your answer is:
Nine million nine hundred thousand five thousand four hundred and eighty two.
Answer:
B. The graph of g(x) is the graph of f(x) horizontally stretched by a factor of 4.
I just did it off of A.P.E.X
Answer:
1.79553
Step-by-step explanation:
Step 1: Write expression
log₁₀(√(69.5² - 30.5²))
Step 2: Evaluate square root
log(√(4830.25 - 930.25))
log(√3900)
log(62.45)
Step 3: Find log
log₁₀ (or log)
log(62.45) = 1.79553
-------------------------------------
To use the table method. we find values that are easily evaluated by log₁₀
log₁₀(10) = 1
log₁₀(50) = 1.69897
log₁₀(100) = 2
So we know that log₁₀(62.45) is between 1 and 2 and greater that 1.69897.
Answer:
6
Step-by-step explanation:
The outlier is 67.
The mean with the outlier is: 115
(112+ 118 + 120 +67 + 128 + 119 + 121 + 124 + 126) ÷ 9
The mean without he outlier is: 121
(112+ 118 + 120 + 128 + 119 + 121 + 124 + 126) ÷ 8
So, 121 - 115 = 6
