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algol13
3 years ago
10

Maria and three friends have a thousand and two hundred stock cards if they share the stock of cards equally how many will each

person receive
Mathematics
1 answer:
andreev551 [17]3 years ago
8 0
1200 ÷ 4 = 300
Each person will receive 300 stock cards.
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the length of each side of a square is 3 in. more than the length of each side of a smaller square. the sum of the areas is 45 i
Marat540 [252]

Answer:

2025 is the answer

Step-by-step explanation:

3 0
3 years ago
Eric has 183 coins all of them are nickels and dimes. If the total value of the coins is 14.45, how many of each denomination co
FromTheMoon [43]

Answer:

77 nickels

106 dimes

Step-by-step explanation:

Let there be n nickes and d dimes

Since there are 183 coins, we can write:

n + d = 183

Also, the value of nickel is 0.05 and dime is 0.1, total value is 14.45, so we can write:

0.05n + 0.1d = 14.45

Solving 1st equation for n, we have:

n = 183 - d

Putting this into 2nd equation and solving for d:

0.05n + 0.1d = 14.45\\0.05(183-d) + 0.1d = 14.45\\9.15-0.05d+0.1d=14.45\\0.05d=5.3\\d=106

There are 106 dimes

Since, n = 183 - d

n = 183 - 106

n = 77

There are 77 nickels

4 0
3 years ago
Plz show ur work! Ty if u do. Will give brainilest!
Sati [7]

Answer:

12/32 divide by 4 and get 3/8 you can’t simplify any further after that

Step-by-step explanation:

5 0
3 years ago
Can someone help me do part two please? It’s very important send a picture or something. I don’t even care if you tell me the st
Nataly_w [17]
<h3>Explanation:</h3>

1. "Create your own circle on a complex plane."

The equation of a circle in the complex plane can be written a number of ways. For center c (a complex number) and radius r (a positive real number), one formula is ...

  |z-c| = r

If we let c = 2+i and r = 5, the equation becomes ...

  |z -(2+i)| = 5

For z = x + yi and |z| = √(x² +y²), this equation is equivalent to the Cartesian coordinate equation ...

  (x -2)² +(y -1)² = 5²

__

2. "Choose two end points of a diameter to prove the diameter and radius of the circle."

We don't know what "prove the diameter and radius" means. We can show that the chosen end points z₁ and z₂ are 10 units apart, and their midpoint is the center of the circle c.

For the end points of a diameter, we choose ...

  • z₁ = 5 +5i
  • z₂ = -1 -3i

The distance between these is ...

  |z₂ -z₁| = |(-1-5) +(-3-5)i| = |-6 -8i|

  = √((-6)² +(-8)²) = √100

  |z₂ -z₁| = 10 . . . . . . the diameter of a circle of radius 5

The midpoint of these two point should be the center of the circle.

  (z₁ +z₂)/2 = ((5 -1) +(5 -3)i)/2 = (4 +2i)/2 = 2 +i

  (z₁ +z₂)/2 = c . . . . . the center of the circle is the midpoint of the diameter

__₁₂₃₄

3. "Show how to determine the center of the circle."

As with any circle, the center is the <em>midpoint of any diameter</em> (demonstrated in question 2). It is also the point of intersection of the perpendicular bisectors of any chords, and it is equidistant from any points on the circle.

Any of these relations can be used to find the circle center, depending on the information you start with.

As an example. we can choose another point we know to be on the circle:

  z₄ = 6-2i

Using this point and the z₁ and z₂ above, we can write three equations in the "unknown" circle center (a +bi):

  • |z₁ - (a+bi)| = r
  • |z₂ - (a+bi)| = r
  • |z₄ - (a+bi)| = r

Using the formula for the square of the magnitude of a complex number, this becomes ...

  (5-a)² +(5-b)² = r² = 25 -10a +a² +25 -10b +b²

  (-1-a)² +(-3-b)² = r² = 1 +2a +a² +9 +6b +b²

  (6-a)² +(-2-b)² = r² = 36 -12a +a² +4 +4b +b²

Subtracting the first two equations from the third gives two linear equations in a and b:

  11 -2a -21 +14b = 0

  35 -14a -5 -2b = 0

Rearranging these to standard form, we get

  a -7b = -5

  7a +b = 15

Solving these by your favorite method gives ...

  a +bi = 2 +i = c . . . . the center of the circle

__

4. "Choose two points, one on the circle and the other not on the circle. Show, mathematically, how to determine whether or not the point is on the circle."

The points we choose are ...

  • z₃ = 3 -2i
  • z₄ = 6 -2i

We can show whether or not these are on the circle by seeing if they satisfy the equation of the circle.

  |z -c| = 5

For z₃: |(3 -2i) -(2 +i)| = √((3-2)² +(-2-i)²) = √(1+9) = √10 ≠ 5 . . . NOT on circle

For z₄: |(6 -2i) -(2 +i)| = √((6 -2)² +(2 -i)²) = √(16 +9) = √25 = 5 . . . IS on circle

4 0
3 years ago
In a football tournament, the Bees scored 9 less than three times as many points as the Hornets. The Wasps scored 28 more points
Elina [12.6K]

Given:

Bees scored 9 less than three times as many points as the Hornets.

Wasps scored 28 more points than the Hornets.

Together the three teams scored 184 points.

To find:

The required equation for this scenario.

Step-by-step explanation:

Let x represent the number of points scored by the Hornets.

Bees scored 9 less than three times as many points as the Hornets.

Bees score = 3x-9

Wasps scored 28 more points than the Hornets.

Wasps score = x+28

Together the three teams scored 184 points.

(3x-9)+x+(x+28)=184

Therefore, the required equation is (3x-9)+x+(x+28)=184.

3 0
3 years ago
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