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mafiozo [28]
3 years ago
14

The answer I got is not one of the options, and I am very confused, because now I don't know what to do?

Mathematics
1 answer:
Effectus [21]3 years ago
4 0
<span>A’(2, -4); B’(7, -9); C’(-2, -9)
I believe you did it correctly but over the wrong line. You were supposed to do it over line M and it looks like you did it over the X-axis.</span>
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AveGali [126]
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2 years ago
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It takes 2 1/2 posterboard to display half of your project how many poster boards will you need for your entire project
murzikaleks [220]
If 2 1/2 posterboard is enough for 1/2 of the project, it will take another 2 1/2 posterboard to display the other half of the project.

2 1/2 + 2 1/2 = 4 + 1/2 + 1/2 = 4 + 1 = 5

Answer: 5 posterboard.
5 0
3 years ago
Please answer hurry!!!!
lutik1710 [3]
The best way to solve this problem is by plugging in each answer choice for both equations and seeing which one works. You can already see that choice A doesn't work because -1 is not greater than or equal to 4. That means you just need to test choices B and C!

Choice B (4, -2)
x + y  \geq 6\\&#10;4 + -2  \geq 6\\&#10;2  \geq  6 &#10;
2 is not greater than or equal to 6, so choice B doesn't work.

Choice C (4, 2)
x + y \geq 6\\ &#10;4 + 2 \geq 6\\ &#10;6 \geq 6 \\\\&#10;x  \geq 4\\&#10;4 \geq 4
Since 6 is equal to 6 and 4 is equal to 4, choice C works!

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Answer: C) (4, 2)
6 0
2 years ago
Choose Yes or No to tell if each statement is true.
aivan3 [116]

Answer:

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Step-by-step explanation:

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hope it helped

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4 0
3 years ago
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Construct 3 linear equation starting with qiven solution z = 1/3
Andreyy89

Answer:

(a)9z+2=5

(b)21z-11=-4

(c)4z=2-2z

Step-by-step explanation:

We are required to construct 3 linear equations starting with the given solution z = 1/3.

<u>Equation 1</u>

<u />z=\frac{1}{3}<u />

Multiply both sides by 9

9z=\frac{1}{3}\times 9\\9z=3

Rewrite 3 as 5-2

9z=5-2

Add 2 to both sides

Our first equation is: 9z+2=5

<u>Equation 2</u>

<u />z=\frac{1}{3}<u />

Multiply both sides by 21

21z=\frac{1}{3}\times 21\\21z=7

Rewrite 7 as 11-4

21z=11-4

Subtract 11 from both sides

Our second equation is: 21z-11=-4

<u>Equation 3</u>

<u />z=\frac{1}{3}<u />

Multiply both sides by 6

6z=\frac{1}{3}\times 6\\6z=2

Rewrite 6z as 4z+2z

4z+2z=2

Subtract 2z from both sides

Our third equation is: 4z=2-2z

4 0
3 years ago
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