Answer:
x≈-2.433 ,x≈2.15
Step-by-step explanation:
For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
For this case we have the following system of equations:
We observe that we have a quadratic equation and therefore the function is a parabola.
We have a linear equation.
Therefore, the solution to the system of equations will be the points of intersection of both functions.
When graphing both functions we have that the solution is given by:
That is, the line cuts the quadratic function in the following ordered pair:
(x, y) = (1, 2)
Answer:
the solution (s) of the graphed system of equations are:
(x, y) = (1, 2)
See attached image.
Answer:
100/2048=0.048828125%
Step-by-step explanation:
He has a 50% chance of making each free-throw, so 1/2*1/2*1/2*1/2*1/2*1/2*1/2*1/2*1/2*1/2*1/2=1/(2^11)=1/2048
to get a percentage you time by 100 to get 100/2048
Answer:
9
Step-by-step explanation:
