All categories

3 years ago

Simplify the expression 63 + 5(4 − 2). Select one: a. 28 b. 36 c. 226 d. 234

2 answers:

3 0

6^3 + 5(4 − 2)
= 216 + 5(2)
= 216 + 10
= 226

based on multiple choice options, 63 = 6^3

so answer is c. 226

Liono4ka [1.6K]3 years ago

3 0

63+5(4-2)
63+5(2)
63+10
=73

You might be interested in

I need help!! Can someone help me?¿

wolverine [178]

Sorry don't know explane the question

7 0

4 years ago

Order from greatest to least 1.202;1.29;1.02

Reptile [31]

Answer:

1.29, 1.202, 1.02

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Helpppppppppppppppp ill mark you brainlist write in y=mx+b form

Alex Ar [27]

Answer:

I think: 0 = 3x + b or b = -3x + 0 or x = -b + 0/3 or 3 = -b + 0/x

Sorry if you get this wrong..

4 0

3 years ago

A new shopping mall is considering setting up an information desk manned by one employee. Based upon information obtained from s

quester [9]

Answer:

a) $P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

b) $p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

c) $L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

d) $L_q =\frac{20^2}{30(30-20)}=1.333 people$

e) $W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

f) $W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

Step-by-step explanation:

Notation

P represent the probability that the employee is idle

$p_x$ represent the probability that the employee is busy

$L_s$ represent the average number of people receiving and waiting to receive some information

$L_q$ represent the average number of people waiting in line to get some information

$W_s$ represent the average time a person seeking information spends in the system

$W_q$ represent the expected time a person spends just waiting in line to have a question answered

This an special case of Single channel model

Single Channel Queuing Model. "That division of service channels happen in regards to number of servers that are present at each of the queues that are formed. Poisson distribution determines the number of arrivals on a per unit time basis, where mean arrival rate is denoted by λ".

Part a

Find the probability that the employee is idle

The probability on this case is given by:

In order to find the mean we can do this:

$\mu = \frac{1question}{2minutes}\frac{60minutes}{1hr}=\frac{30 question}{hr}$