Given :
Michaela runs to the end of her street and back in 90 s.
Her brother, Jacob, walks to the end of the street and back in 3 min.
They both run or walk for the same amount of time, but Michaela makes 5 more trips than Jacob.
To Find :
How many times did each person go to the end of the street and back.
Solution :
Let, they both walk for T seconds.
Number of rounds Michaela walk is, n₁ = T/90 .
Number of rounds Jacob walk is, n₂ =T/180 .
It is given that :
n₁ = n₂ + 5
T/90 + T/180 = 5
( T/90 + T/180 ) × 180 = 5×180
2T + T = 900
3T = 900
T = 300 s
So, n₁ = 300/90 = 3
n₂ = 1
Hence, this is the required solution.
Answer: 1.06
Step-by-step explanation:
This is the answer because the price of the shoes is s, and the tax is 0.06s. The total cost of the shoes with tax is s+0.06s= 1.06s
Answer:
A.) 7x x 5=$50.00
Step-by-step explanation:
You can eliminate B and C as they don't include the 5 different stores.
D is incorrect because it doesn't include the 7 items.
Therefore, A is correct because 7x is the 7 items multiplied by the average cost per item and you multiply by 5 because she does that at each of the 5 stores. It = to 50 because she started with $65 but ends up with $15 so you subtract $65 with $15 to get $50 as that's how much she spent.
Hmm. 8 1/5 minus 4 and 2/5 i like to make this easier by changing into fractions
41/5 minus 22/5
its 19/5
change back into mixed number.
3 4/5
