To solve for the missing steps, let's rewrite first the problem.
Given:
In a plane, line m is perpendicular to line t or m⟂t
line n is perpendicular to line t or n⟂t
Required:
Prove that line m and n are parallel lines
Solution:
We know that line t is the transversal of the lines m and n.
With reference to the figure above,
∠ 2 and ∠ 6 are right angles by definition of <u>perpendicular lines</u>. This states that if two lines are perpendicular with each other, they intersect at right angles.
So ∠ 2 ≅ ∠ 6. Since <u>corresponding</u> angles are congruent.
Therefore, line m and line n are parallel lines.
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<em>ANSWERS: perpendicular lines, corresponding</em>
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50 points decreased by 26% is
37 points.

50 points decreased by 26% is
37 points.
Answer:
y= -6+2/3x
Step-by-step explanation:
2x-3y=18
Minus the 2x from both sides
-3y=18-2x
Then divide both sides by -1
-3y÷-1=18÷-1 -2x÷-1
Lastly divide both sides by 3
3y÷3= -18÷3+2x÷3
I think the answer is b. cos(pi theta)= -0.6
I don't know how you expand it but the answer is 3x + 25 unless that's expanding.