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REY [17]
2 years ago
10

3. The electric current, C, in amperes, in a circuit varies directly as the voltage, V. When 12 volts are

Mathematics
1 answer:
Kazeer [188]2 years ago
8 0
The answer of this question is B
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Rewrite each expression by factoring out the greatest common factor.
astra-53 [7]

Answer:

7(X+2)

5(Y-5)

(-3X-3^3)

-3(X+1^3)

8 0
3 years ago
The perimeter of a rectangle is 338, if the ratio of the length to the width is 8:5, find the length
STALIN [3.7K]
Let the length be 8x and the width = 5x, then
Perimeter = 2(length + width) = 2(8x + 5x) = 2(13x) = 26x
338 = 26x
x = 338/26 = 13

Therefore, length = 8x = 8 x 13 = 104
4 0
3 years ago
Solve each system by elemination, 4x+8y=20 and -4x+2y=-30
ludmilkaskok [199]
The sum of the left side of these two equations is equal to the same of the right side is these two equations
4x+8y + (-4x+2y) = 20 + 30
10y =50 ( x is eliminated)
y=5
Take this into the second equation
-4x +2y = 30
-4x + 2*5 = 30
x=-5

So x=-5
y=5
5 0
3 years ago
A North American river otter wants to cross the North Saskatchewan river. It can swim at a speed of 2.75 m/s. In that location,
insens350 [35]

Answer:

Step-by-step explanation:

time to cross will be the distance divided by the velocity in that direction.

a) t = d/v = 45/2.75 = 16.363636... 16.4 s

In the same time that the otter is swimming cross stream, the stream is also moving perpendicularly at its own pace.

b) d = vt = 2.5(16.36) = 40.9090... 40.9 m

As velocity is a vector, An observer on the bank would see the velocity as the vector addition of the cross stream and down stream velocities

c) v = √(2.75² + 2.5²) = 3.716517... 3.72 m/s  magnitude

  θ = arctan2.5/2.75 = 42.2736... 42.3° downstream of a line straight across

7 0
3 years ago
If f(x) = kx^3+ x^2 − kx + 2, find a number k such that the graph of f contains the point (k, -10)
Elina [12.6K]

If we write k where we see x in the equation and set the result equal to -10, we get the result.

  • f(k)=k(k)^3+k^2-k(k)+2
  • =k^4+k^2-k^2+2
  • =k^4+2=-10
  • k^4=-12
  • k_{1}=\sqrt[4]{3}(-1-i)
  • k_{2}=\sqrt[4]{3}(-1+i)
  • k_{3}=\sqrt[4]{3}(1-i)
  • k_{4}=\sqrt[4]{3}(1+i)

4 0
1 year ago
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