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astra-53 [7]
3 years ago
14

Determine the standard form of the equation of the line that passes through (-7,8) and (0,-8)

Mathematics
1 answer:
faust18 [17]3 years ago
8 0

Answer:

work shown and pictured

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In basketball, baskets are worth either 2 or 3 points. A missed shot, of course, is worth 0 points. During the 2007-2208 season,
rosijanka [135]

Answer:

1.15

Step-by-step explanation:

Multiply each shot by its point value. Then add. Divide this sum by the total number of shots taken.

288*2 + 79*3 + 340*0 = 813

----------------------------------------

288 + 79 + 340 = 707

813 / 707 = 14.992

The weighted average is approximately 1.15 points per shot.

7 0
2 years ago
Amir has a bag of dimes and quarters. He has a total of 31 coins worth $5.20.
Step2247 [10]

Answer

B is the correct answer.

Step-by-step explanation:

This is the given information for which system of equations would be used to find out how many dimes and quarters Amir has?

x = dimes          x = 0.10 or 0.1

y = quarters      y = 0.25

31 coins

worth $5.20       = 5.2

x + y = 31

0.1x + 0.25y = 5.2

3 0
3 years ago
Question 2
dolphi86 [110]

Answer:

answer J

Step-by-step explanation:

srry if im wrong  hope it helps:)

8 0
3 years ago
Simplfy 1/4 (q-16)+1/3(q+12)
ValentinkaMS [17]

Answer:

7q is the numerator which is the top and the denominator is 12 which is the bottom number.

Step-by-step explanation:

4 0
2 years ago
PLEASE HELP ME with an explanation. Thanks in advance
REY [17]

Answer:

3) 0.30

The probability a randomly selected<em> student plays a sport</em> given they work part time = 0.30

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given  'A' plays a sport

          B work part time

Given P(A) = 0.48

         P(B)  = 0.40

        P(A∩B) =0.12

       P(A∪B)¹ =0.24

<u><em>Step(ii)</em></u>:-

By using conditional probability

P(B/A) = \frac{P(BnA}{P(A)}

and similarly P(A/B) = \frac{P(AnB}{P(B)}

The probability a randomly selected<em> student plays a sport</em> given they work part time

Now P(A/B) = \frac{P(AnB}{P(B)}

       P(A/B) = \frac{0.12}{0.40}= 0.30

<u>Final answer</u>:-

The probability a randomly selected<em> student plays a sport</em> given they work part time = 0.30

8 0
3 years ago
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