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3 years ago

Help please..............

Mathematics

1 answer:

eimsori [14]3 years ago

6 0

I believe the correct answer here would be B. The values x=2 and y=5 make the equation true. The answer is not A, because the graph could also go through 3 and 6. It is not C because that is not the correct order. The answer is not D because D is absurd and does not make sense.

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What kind of motion do people have on an escalator

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Step-by-step explanation:

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3 years ago

Read 2 more answers

1-Describe the error in the way the calculation of the slope of the two points is set up and/or solved. Please be specific. Do n

Bad White [126]

Answer:

Please check explanations for answer

Step-by-step explanation:

Let’s have two points (5,10) and (15,20)

1. Let’s find the slope of these two points

Mathematically, the slope can be calculated using the formula;

m = (y2-y1)/(x1-x2)

So m = (20-10)/(5-15) = 10/-10 = -1

The error here is the formula used in calculating the slope

The formula should be;

m = (y2-y1)/(x2-x1) and not x1-x2

2. To calculate the slope correctly, we have;

m = (y2-y1)/(x2-x1)

So the slope will be;

m = (20-10)/(15-5) = 10/10 = 1

In the point slope form, the equation can be represented as;

y-y1 = m(x-x1)

Let’s use the point (5,10)

y- 10 = 1(x-5)

The above is the point slope form

using one of the points and the correct slope of the line

6 0

3 years ago

Find the average value of f over region

SVETLANKA909090 [29]

$D$ is a right triangle with base length 1 and height 8, so the area of $D$ is $\dfrac12(1)(8)=4$ .

The average value of $f(x,y)$ over $D$ is given by the ratio

$\dfrac{\displaystyle\iint_Df(x,y)\,\mathrm dA}{\displaystyle\iint_D\mathrm dA}$

The denominator is just the area of $D$ , which we already know. The average value is then simplified to

$\displaystyle\frac74\iint_Dxy\,\mathrm dA$

In the $x,y$ -plane, we can describe the region $D$ as all points $(x,y)$ that lie between the lines $y=0$ and $y=8x$ (the lines which coincide with the triangle's base and hypotenuse, respectively), taking $0\le x\le1$ . So, the integral is given by, and evaluates to,

$\displaystyle\frac74\int_{x=0}^{x=1}\int_{y=0}^{y=8x}xy\,\mathrm dy\,\mathrm dx=\frac78\int_{x=0}^{x=1}xy^2\bigg|_{y=0}^{y=8x}\,\mathrm dx$
$=\displaystyle56\int_{x=0}^{x=1}x^3\,\mathrm dx$
$=14x^4\bigg|_{x=0}^{x=1}$
$=14$

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3 years ago

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hram777 [196]

2.2345679012 I THINK

4 0

3 years ago

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Answer:

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2 years ago