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AVprozaik [17]
3 years ago
5

3/7 x =5/14 solve for X

Mathematics
1 answer:
Paul [167]3 years ago
7 0

Answer:

\frac{5}{6} = x

Step-by-step explanation:

\frac{3}{7}x = \frac{5}{14} \\ \\ \frac{5}{14} \div \frac{3}{7} = \frac{5}{14} \times \frac{7}{3} = \frac{35}{42} = \frac{5}{6}

Use multiplication [inverse of division] to figure this out.

* 2⅓ = 7⁄3

I am joyous to assist you anytime.

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Hope this helps! ;)

5 0
4 years ago
Can someone help me with this please? I will mark you brainliest
lina2011 [118]

Answer:

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On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Step-by-step explanation:

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3 years ago
Can someone help? And yes it shows the whole page! :)
cricket20 [7]

Uhh the the Nader ic clearing at the back page

8 0
4 years ago
What is the value of x in the equation -2/3x + 9 = 4/3x - 3 ?​
Ainat [17]

Answer:

x = 1/6

Step-by-step explanation:

hope it helps.

x= 1/6

6 0
3 years ago
Read 2 more answers
1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch
kykrilka [37]
Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle. 

Thus, half the angle formed by the chord at the centre of the circle is given by:

\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2}  \\  \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o

Now, 

\sin60^o= \frac{9}{r}  \\  \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392

Therefore, the radius of the circle is 10.4 cm to 1 d.p.


Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o

Now, 

\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm


Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

\sin40^o= \frac{y}{10}  \\  \\  \\ \Rightarrow y=10\sin40^o=6.428

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.
3 0
3 years ago
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