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HACTEHA [7]
3 years ago
11

What is the following quotient? 6-3(3 √8)/3 √9

Mathematics
2 answers:
Vilka [71]3 years ago
8 0

Answer:

The correct option is A) 2\sqrt[3]{3}-{\sqrt[3]{18}

Step-by-step explanation:

Consider the provided expression.

\frac{\left(6-3\left(\sqrt[3]{6}\right)\right)}{\sqrt[3]{9}}

Rationalize by multiplying conjugate \frac{9^{\frac{2}{3}}}{9^{\frac{2}{3}}}

\frac{\left(6-3\sqrt[3]{6}\right)\cdot \:9^{\frac{2}{3}}}{\sqrt[3]{9}\cdot \:9^{\frac{2}{3}}}

\frac{9^{\frac{2}{3}}\cdot \:3\left(2-\sqrt[3]{6}\right)}{9}

\frac{9^{\frac{2}{3}}\left(2-\sqrt[3]{6}\right)}{3}

\frac{3^{\frac{4}{3}}\left(2-\sqrt[3]{6}\right)}{3}

3^{\frac{1}{3}}\left(2-\sqrt[3]{6}\right)

2\sqrt[3]{3}-3^{\frac{2}{3}}\sqrt[3]{2}

2\sqrt[3]{3}-{\sqrt[3]{18}

Hence, the correct option is A) 2\sqrt[3]{3}-{\sqrt[3]{18}

WARRIOR [948]3 years ago
5 0

Answer:

Factor the numerator and denominator and cancel the common factors.

Exact Form:

2

3

√

3

−

3

√

18

Decimal Form:

0.26375774

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The following data represent the pH of rain for a random sample of 12 rain dates in Tucker County, West Virginia. A normal proba
Sphinxa [80]

Answer:

Step-by-step explanation:

n = 12

Mean = (4.58 + 5.72 + 4.77 + 4.76 + 5.19 + 5.05 + 4.80 + 4.77 + 4.75 + 5.02 + 4.74 + 4.56)/12 = 4.8925

Standard deviation = √(summation(x - mean)²/n

Summation(x - mean)² = (4.58 - 4.8925)^2 + (5.72 - 4.8925)^2 + (4.77 - 4.8925)^2 + (4.76 - 4.8925)^2 + (5.19 - 4.8925)^2 + (5.05 - 4.8925)^2 + (4.80 - 4.8925)^2 + (4.77 - 4.8925)^2 + (4.75 - 4.8925)^2 + (5.02 - 4.8925)^2 + (4.74 - 4.8925)^2 + (4.56 - 4.8925)^2 = 1.122225

Standard deviation = √(1.122225/12

s = 0.31

a) Point estimate = sample mean = 4.8925

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

Margin of error = z × s/√n

Where

From the information given, the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 12 - 1 = 11

b) Since confidence level = 95% = 0.95, α = 1 - CL = 1 – 0.95 = 0.05

α/2 = 0.05/2 = 0.025

the area to the right of z0.025 is 0.025 and the area to the left of z0.025 is 1 - 0.025 = 0.975

Looking at the t distribution table,

z = 2.201

Margin of error = 2.201 × 0.31/√12

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Upper limit = 4.8925 + 0.197 = 5.0895

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c) For 99% confidence level, z = 3.106

Margin of error = 3.106 × 0.31/√12

= 0.278

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Upper limit = 4.8925 + 0.278 = 5.1705

Lower limit = 4.8925 - 0.278 = 4.6145

We are 99% confident that the population mean of the rain water ph lies between 4.6145 and 5.1705

d) The interval gets wider as the confidence level is increased. This is logical since the test score is higher for 99% and therefore, increases the range of values. Since we want to be more confident, the range of values must be extended.

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Step-by-step explanation:

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We simply graph the function and determine the points where it crosses the x-axis. From the attachment, f(x) crosses the x-axis at;

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