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3 years ago

A rectangle has a length of x and a width that is 8 units shorter than twice the length.

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

6 0

Step-by-step explanation:

length = x

width = 2x-8

b.) to get the area you need to multiply the length and the width.

l×w= area

x(2x-8)

2x^2-8x

c.) 2x^2-8x = 10

subtract 10 both sides

2x^2-8x-10 = 0

2(x^2-4x-5) = 0

2(x-5)(x+1) = 0

x = 5

the area would be 10.

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We have two forces as follows:

<u>First force:</u>

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Angle: 30°

<u>First force:</u>

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So the components can be found as follows:

$F_{1x}=150cos(30)=129.90 \ lbf\\F_{1y}=150sin(30) = 75 \ lbf \\ \\ F_{2x}=100cos(120)=-50 \ lbf\\F_{2y}=100sin(120) = 86.60 \ lbf$

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