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german
3 years ago
8

Why is finding the factor pairs only the first step in solving the problem

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0
So you can know which pair to use in order to solve the problem.
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Idk Help meee please
nordsb [41]

Answer:

-9 =x

Step-by-step explanation:

We know these are similar triangles

We can use ratio's to solve

Let CS = y  and XR = y+y or 2y

y           x+19

------ = ------------

2y         x+29

We can simplify the ratio on the left by dividing by y

1           x+19

------ = ------------

2         x+29

Using cross products

1(x+29) = 2(x+19)

Distribute

x+29 = 2x+38

Subtract x from each side

x-x+29 = 2x-x+38

29 = x+38

Subtract 38 from each side

29-38= x+38-38

-9 =x

8 0
3 years ago
What is the value of f^{-1}(4)f
charle [14.2K]

Answer:-7

Step-by-step explanation:

trust me lol

4 0
3 years ago
Read 2 more answers
What is the area of the piece of red paper after the hole for
MakcuM [25]

Answer:

     \large\boxed{\large\boxed{47unit^2}}

Explanation:

The complete question is:

<em>A hole the size of a photograph is cut from a red piece of paper to use in a picture frame.</em>

<em />

<em>On a coordinate plane, 2 squares are shown. The photograph has points (-3, -2), (- 2, 2), (2, 1), and (1, -3). The red paper has points (- 4, 4), (4, 4), (4, -4), and (-4, -4).</em>

<em />

<em>What is the area of the piece of red paper after the hole for the photograph has been cut?</em>

<em />

<h2><em>Solution</em></h2>

<em />

The area of the piece of redpaper after the hole has been cut is equal to the area of the big square less the area of the small rectangle.

<u>1. Area of the big rectangle</u>

Vertices:

  • <em>(- 4, 4) </em>
  • <em>(4, 4)</em>
  • <em>(4, -4)</em>
  • <em>(-4, -4)</em>

<em />

The side length is the distance between two consecutive vertices:

The two points (-4,4) and (4,4) has the same y-coordinate, thus the length is just the absolute value of the difference of the x-coordinates:

  • 4-(-4)=4+4=8

The area of this square is    (8unit)^2=64unit^2

<u>2. Area of the small square</u>

Vertices:

  • <em>(-3, -2)</em>
  • <em>(- 2, 2) </em>
  • <em>(2, 1)</em>
  • <em>(1, -3)</em>

<em />

To find the side length use the distance formula for two consecutive points, for instance (2,1) and (-2,2):

      d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\ \\d=\sqrt{(2-(-2))^2+(2-1)^2}=\sqrt{4^2+1^2}=\sqrt{17}

The area is:

          (\sqrt{17}unit)^2}=17unit^2

<u>3. Area of the piece of red paper after the holw for the photograph has been cut:</u>

<u />

Find the difference:

<u />

         64unit^2-17unit^2=47unit^2

<em />

7 0
3 years ago
Read 2 more answers
Activity 2
Vsevolod [243]
The unknown is 2% and sorry
7 0
3 years ago
Evaluate this expression. (−36.28) + (−83.73)
sergeinik [125]

Answer:

-120.01

Step-by-step explanation:

I just took the test

3 0
2 years ago
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