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german
3 years ago
8

Why is finding the factor pairs only the first step in solving the problem

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0
So you can know which pair to use in order to solve the problem.
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I’ll put you as brainliest
kari74 [83]

The law of an object moving with constant acceleration is

s(t)=s_0+v_0t+\dfrac{1}{2}at^2

Where s is space, t is time, s_0 is the initial position, v_0 is the initial velocity and a is the acceleration.

In this case, if we choose a reference grid with the vertical axis pointing upwards, the acceleration of gravity will point downwards (and thus be negative). The initial position is zero, because the rocket is on the ground, and the initial velocity is 100 (positive because pointing upwards).

So, its law is

h(t)=100t-\dfrac{1}{2}gt^2

(I changed s for h since the rocket is moving vertically, so its position is actually its height. Also, g is the acceleration due to gravity).

The rocket hits the ground if its height is zero, so if we set h=0 we have

0=100t-\dfrac{1}{2}gt^2 \iff t(100-\dfrac{1}{2}gt)=0

Solving for t, we have either t=0, or

100-\dfrac{1}{2}gt=0 \iff 100=\dfrac{1}{2}gt \iff 200=gt \iff t=\dfrac{200}{g}

The solution t=0 means that at the beginning the rocket is on the ground. So, we're interested in the other solution. Considering that g is about 32.2 feet/s^2, we have

t=\dfrac{200}{g}\approx \dfrac{200}{32.2}\approx 6.21

3 0
3 years ago
Which linear inequality is represented by the graph?
Rasek [7]

Answer:

y> 3x + 2

Step-by-step explanation:

Hope it is helpful....

6 0
3 years ago
PLEASE HELP ME, THIS MEANS EVERYTHING TO ME ITS APART OF MY FINALS.❗
Alenkinab [10]

Answer:

Uhhhh... 54?

Step-by-step explanation:

Just add them together.

3 0
3 years ago
Let f and g be differentiable functions such that f(1) = 2, f'(1) = 3, f'(2) = -4, g(1) = 2, g'(1) = -3, g'(2) = 5. If h(x) = f
crimeas [40]

Answer:

12

Step-by-step explanation:

h(x) = f(g(x))

Using chain rule:

h'(x) = f'(g(x)) g'(x)

h'(1) = f'(g(1)) g'(1)

h'(1) = f'(2) g'(1)

h'(1) = -4 × -3

h'(1) = 12

7 0
3 years ago
What value of m does the graph y = 18x2 + mx + 2 have exactly one x-intercept?
Vlada [557]
To get the graph to have one x-intercept, we must find the m value where the discriminant of the equation will equal 0.

The discriminant for a graph with one x-intercept is found with the following formula:

b^2 - 4ac = 0

Plug in the values of the equation into this formula:

\text{a = 18, b = m, c = 2}
m^2 - 4(18)(2) = 0
m^2 - 144 = 0

Add 144 to both sides:

m^2 = 144

Square root both sides to get m by itself:

\sqrt{144} = \pm 12
m = 12, \ m = -12

In order for the graph to have one x-intercept, m must equal -12 or 12.
7 0
4 years ago
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