Answer:
Multiply then add them and them that's your answer.
Step-by-step explanation:
we are given with two dice and that we are asked in the problem to find the probability of the following:
a. sum at least 4b. sum at least 6
THe sample space of this problem is
{11, 12, 13, 14, 15, 16, 21,22, 23,24,25,26,31,32,33,34,35,36,41,42,43,44,45,46,51,52,53,54,55,56,61,62,63,64,65,66} a total of 36.a. 33/36 = 11/12b.11/36
The height is 1, because it's A=(b1 + b2)*h, the equation is this now 7=3 + 4)*h, you add 3 + 4 then that will give you 7, so now it should look like this 7=7*h, you do a fraction line under the 7 and 7*h each, and put a 7 as the denominator, so it kind of looks like this now 7 = 7*h
__ __
7 7 then you cancel the 7*h which leaves you to just h, so 7 divided by 7 will give you 1 so it looks like 1=h, PHEW
10y+50
Answer:
10(y+5)=10y+50
just
multiplying both by 10.Use distribute property.
