complete question:
A fountain is made up of two semicircles and a quarter circle. The diameter of the semicircles is 10 ft. Find the perimeter of the fountain. Round your answer to the nearest tenth. The picture is represented below.
Answer:
The perimeter of the fountain = 47.1 ft
Step-by-step explanation:
The fountain has 2 semi circle from a smaller circle with the diameter represented as 10 ft and a quarter circle from a bigger circle with the radius equals to 10 ft.
The perimeter is the distance around the fountain.The perimeter is the circumference in circular perspective. Therefore,
perimeter for a full circle = 2πr
Half circle = 2πr/2 = πr
For 2 half circle = πr + πr = 2πr
For 2 half circle = 2πr
r = 10/2 = 5
perimeter for 2 half circle = 2 × 5 × 3.14 = 31.4 ft
Perimeter for the quarter circle
r = 10 ft
Quarter circle perimeter = 1/4 × 2πr = πr/2
Quarter circle perimeter = (3.14 × 10)/2
Quarter circle perimeter = (31.4)/2
Quarter circle perimeter = 15.7 ft
The perimeter of the fountain = 15.7 ft + 31.4 ft = 47.1 ft
I would say that he divided each rectangle in 12 identical parts
for the first rectangle he shaded 1/3 of 12 = 4 parts
for the second rectangle he shaded 1/4 of 12= 3 parts
so 12= 3*4 leads to a minimum of 12 parts
:)
Answer:
x<5
Step-by-step explanation:
the greater sign will firstly be changed to = for better solving so we obtain
3+9x=4(x+7)by opening bracket
3+9x=4x+28
9x-4x=28-3
5x=25
divide all through by 5x
we obtain
x=5
the greater sign change here
which is x<5
Answer:
Explanation:
Please follow the diagram in attachment.
As we know median from vertex C to hypotenuse is CM
We are given length of CG=4
Median divide by centroid 2:1
CG:GM=2:1
Where, CG=4
ft
Length of CM=4+2= 6 ft
In
Using trigonometry ratio identities
ft
ft
ft
In
Using pythagoreous theorem
Length of AG=2/3 AN
ft