Question

What values of b satisfy 4(3b + 2)2= 64

Answer 1

Answer:

b = 2

Step-by-step explanation:

4(3b+2)2 = 64

4×2=8

8(3b+2) = 64

$\frac{8(3b+2)=64}{8}$    Divide by 8 on both sides of equation.

3b+2 = 8     Subtract 2 from both sides of equation.

    -2    -2

$\frac{3b = 6}{3}$              Divide by 3 on both sides of equation.

b = 2