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2 years ago

What values of b satisfy 4(3b + 2)2= 64

Mathematics

1 answer:

Andreas93 [3]2 years ago

6 0

Answer:

b = 2

Step-by-step explanation:

4(3b+2)2 = 64

4×2=8

8(3b+2) = 64

$\frac{8(3b+2)=64}{8}$ Divide by 8 on both sides of equation.

3b+2 = 8 Subtract 2 from both sides of equation.

-2 -2

$\frac{3b = 6}{3}$ Divide by 3 on both sides of equation.

b = 2

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3 years ago

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