Question

What quantity of 78% chlorine solution must be mixed with a 23% chlorine solution to produce 477.16 mL of 60% solution?

Answer 1

Answer:

321 mL of 78% chlorine solution must be mixed with 156.16 mL of 23% chlorine solution

Step-by-step explanation:

Let

x ----> quantity of 78% chlorine solution in milliliters

y ----> quantity of 23% chlorine solution in milliliters

we know that

The quantity x of 78% chlorine solution mixed with a quantity y of 23% chlorine solution produce 477.16 mL of 60% solution

$78\%=78/100=0.78\\23\%=23/100=0.23\\60\%=60/100=0.60$

so

$x+y=477.16$ ----> equation A

$0.78x+0.23y=0.60(477.16)$

$0.78x+0.23y=286.296$ ----> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (321, 156.16)

therefore

321 mL of 78% chlorine solution must be mixed with 156.16 mL of 23% chlorine solution