2 answers:
You might be interested in
To find the answer we have to slowly analyze the command.
For surely on the one side we want to have total cash spent, so 80.8$
We know that there are 2 types of frames 5,80$ and 9.60$.
We know too, that f is the number of frames 5.80$ bought.
Simply, to find the cash spent on those frames we have to just mulitply 5.80$ times f, so we obtain
.
We can say that number of bigger frames is 20-f.
So to find cash spent on bigger frames we have to multiply 9.60$ times (20-f), so
Now we can just add cost of all frames together
And we know that is equal to 80.8, so
=80.8
As we can see, the answer is b.
For surely on the one side we want to have total cash spent, so 80.8$
We know that there are 2 types of frames 5,80$ and 9.60$.
We know too, that f is the number of frames 5.80$ bought.
Simply, to find the cash spent on those frames we have to just mulitply 5.80$ times f, so we obtain
We can say that number of bigger frames is 20-f.
So to find cash spent on bigger frames we have to multiply 9.60$ times (20-f), so
Now we can just add cost of all frames together
And we know that is equal to 80.8, so
As we can see, the answer is b.
Answer:
58 students
Step-by-step explanation:
Given
Required
Students that take only 1 subjects
The attached image illustrates the question.
For French only (x), we have:
Collect like terms
For Geometry only (y), we have:
Collect like terms
For History only (z), we have:
Collect like terms
Students with one subject is then calculated as:
