Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
Answer:
7325.34
Step-by-step explanation:
Let's convert the equation in point-slope form to slope-intercept form.
y - 4 = -(x - 6)
Multiply everything out.
y - 4 = -x + 6
Add 4 to both sides.
y = -x + 10
To be perpendicular, the slope of the new has to be the reciprocal of the other line. To slope in this equation is -1/1. To get the reciprocal, flip the numerator and denominator and change the sign too.
-1/1 becomes 1/-1, and changes to 1/+1, or 1.
y = x + b
Input the coordinate point and solve for b.
-2 = -2 + b
Add 2 to both sides.
0 = b
y = x
Answer:
sorry I need points
Step-by-step explanation:
so so sorry
