The answer is false due to the object is changes shape not size
It hits the ground at h=0
0=-16t^2-16t+96
undistribute -16
0=-16(t^2+t-6)
factor
0=-16(t-2)(t+3)
set to zero
0=t-2
2=t
t+3=0
t=-3, nope, we can't have negative time
at t=2, or 2 seconds
15y = 7x + 8
15y - 7x - 8 = 0
i am a mathematics teacher. if anything to ask please pm me
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