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Phantasy [73]
3 years ago
11

Lee spent 1/3 of his money on a jacket then he spent 1/4 of he remainder on a skirt how much did his spend on the skirt and how

much did he start with.
Mathematics
1 answer:
serg [7]3 years ago
6 0
How is it possible to know how much he started with? Or is it not asking for an exact amount?
You might be interested in
-5 = x divided by 2.4
snow_tiger [21]

Answer:

x=12

Step-by-step explanation:

-5= x/2.4

multiply both sides by 2.4 to isolate x

-5*2.4= (x/2.4)*2.4

12=x

5 0
3 years ago
The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth
Gala2k [10]

Answer:

(a) There are 70 different ways set up 4 computers out of 8.

(b) The probability that exactly three of the selected computers are desktops is 0.305.

(c) The probability that at least three of the selected computers are desktops is 0.401.

Step-by-step explanation:

Of the 9 new computers 4 are laptops and 5 are desktop.

Let X = a laptop is selected and Y = a desktop is selected.

The probability of selecting a laptop is = P(Laptop) = p_{X} = \frac{4}{9}

The probability of selecting a desktop is = P(Desktop) = p_{Y} = \frac{5}{9}

Then both X and Y follows Binomial distribution.

X\sim Bin(9, \frac{4}{9})\\ Y\sim Bin(9, \frac{5}{9})

The probability function of a binomial distribution is:

P(U=k)={n\choose k}\times(p)^{k}\times (1-p)^{n-k}

(a)

Combination is used to determine the number of ways to select <em>k</em> objects from <em>n</em> distinct objects without replacement.

It is denotes as: {n\choose k}=\frac{n!}{k!(n-k)!}

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

{8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\  =0.304832\\\approx0.305

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

P(Y\geq 3)=1-P(Y

Thus, the probability that at least three of the selected computers are desktops is 0.401.

6 0
3 years ago
A barrier in the shape of a rectangle is used to retain oil spills. On a blueprint, a similar barrier is 9 inches long and 2 inc
drek231 [11]

Width of the actual barrier = 1.2 miles

Width of the barrier in the blueprint = 2 inches

2 inch dimension of blueprint = 1.2 miles of original

So, 1 inch dimension of blueprint = 1.2/2 = 0.6 miles.

Since the length of the barrier in the blueprint = 9 inches,

length of the actual barrier = 9(0.6) = 5.4 miles.

5 0
3 years ago
Write a number that is 10 times what the 6 represents in 36429
artcher [175]
The 6 represents 6,000, so 6,000 times ten is 60,000
7 0
3 years ago
Find the sum: 6 + (-2)
Dovator [93]

Answer:

4

Step-by-step explanation:

See you add negative 2, to 6 so if you add -2  to 6 you will get 4

3 0
2 years ago
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