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igomit [66]
3 years ago
15

Trapezoid W′X′Y′Z′ ​ is the image of trapezoid WXYZ under a dilation through point C.

Mathematics
2 answers:
dem82 [27]3 years ago
8 0

Answer:

Option C.

Step-by-step explanation:

Given information: WX=8m and W'X'=6m

It is given that Trapezoid W′X′Y′Z′ ​ is the image of trapezoid WXYZ under a dilation through point C.

Scale factor is the ratio of corresponding sides of image and preimage.

\text{Scale factor}=\frac{Corresponding side of image}{Corresponding side of preimage}

For the given figure,

\text{Scale factor}=\frac{W'X'}{WX}

\text{Scale factor}=\frac{6}{8}

\text{Scale factor}=\frac{3}{4}

Since image and preimage lie on the same side of the center of dilation. So, the scale factor is positive number.

Therefore, the correct option is C.

Luda [366]3 years ago
4 0

The answer is 3 over 4

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Solve simultaneously <br> 3x + 4y = 2 and 4x - y = 9
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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
graph each equation for the interval -360 is less than or equal to x and 360 is greater than or equal to x: y=1/2cos(2x+60)
lianna [129]

Answer:

See graph

Step-by-step explanation:

We want to graph y=\frac{1}{2}\cos(2x+60\degree) on the interval -360\degree \le x \le 360\degree

We need to plot some few points

(-30\degree,\frac{1}{2})

(-15\degree,\frac{\sqrt{3}}{4})

(0\degree,\frac{1}{4})

(15\degree,0)

(30\degree,-\frac{1}{4})

(45\degree,-\frac{\sqrt{3}}{4})

(60\degree,-\frac{1}{2})

(75\degree,-\frac{\sqrt{3}}{4})

(90\degree,-\frac{1}{4})

(105\degree,0)

(120\degree,\frac{1}{4})

(135\degree,\frac{\sqrt{3}}{4})

(150\degree,\frac{1}{2})

This will give us one cycle.

We then use the pattern to complete the graph on the interval

-360\degree \le x \le 360\degree

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Need help solving this D:
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Answer:

Step-by-step explanation:

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