a. 7x + 52 (2x + 5x) (40 + 12)
b. 13x + 142 (2x+5x+6x) (40 + 12 - 10)
c. 246 (16 + 40 + 40 + 100 + 12 + 48 - 10)
Answer:
C(5,-9) and r=8.
Step-by-step explanation:
C(p, q) - center
r=radius
k:x^2 +y^2 +dx+ey+f=0
x^2+y^2 - 10x+18y+42=0
d=-10, e=18, f=42
p=-d/2=-(-10)/2=10/2=5
q=-e/2=-18/2=-9
r^2 =p^2+q^2-f
r^2 =5^2 +(-9)^2 - 42
r^2=25+81-42
r^2 =106-42
r^2 =64
r=sqrt(64)
r=8
C(p,q)=C(5,-9) r=8
Answer:
f⁻¹(x) = x - 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Functions
- Function Notation
- Inverse Functions
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
f(x) = x + 3
<u>Step 2: Find</u>
- Swap: x = y + 3
- [Subtraction Property of Equality] Isolate <em>y</em>: x - 3 = y
- Rewrite: f⁻¹(x) = x - 3
Answer:
a: z = -1.936
b: 0.0265
d: z < -1.645
Reject H0 if z < -1.645
Step-by-step explanation:
We are given:
H0: µ = 20
HA: µ < 20
n = 60, sample mean: 19.6, σ = 1.6
Since the alternate hypothesis has a < sign in it, it is a left tailed test. The < or > sign in the alternate hypothesis points towards the rejection region.
For a: We need to calculate the test statistic for our situation. This is done with a z-score formula for samples.
For b: we need to use the z-score table to look up the p-value for the score we calculate in part a. The p-value is 0.0265. This means that there is only about a 2.65% chance that the sample values were a result of random chance.
For d: Since the significance level is 0.05, and this is a one tailed test, we have a critical value of z < - 1.645. This means that if the z-score we calculate in part a is less than -1.645, we will reject the null hypothesis
See attached photo for all the calculations!