The average rate of change is 0.19
Answer: a. 0.6759 b. 0.3752 c. 0.1480
Step-by-step explanation:
Given : The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes
i.e.
minutes
minutes
Let x be the long-distance call length.
a. The probability that a call lasts between 5 and 10 minutes will be :-

b. The probability that a call lasts more than 7 minutes. :
![P(X>7)=P(\dfrac{X-\mu}{\sigma}>\dfrac{7-6.3}{2.2})\\\\=P(Z>0.318)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E7%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B7-6.3%7D%7B2.2%7D%29%5C%5C%5C%5C%3DP%28Z%3E0.318%29%5C%20%5C%20%5C%20%5C%20%5Bz%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-P%28Z%3C0.318%29%5C%5C%5C%5C%3D1-0.6248%5C%20%5C%20%5C%20%5C%20%5B%5Ctext%7Bby%20z-table%7D%5D%5C%5C%5C%5C%3D0.3752)
c. The probability that a call lasts more than 4 minutes. :

Answer:
Step-by-step explanation:
hg(x) means you multiply h(x) times g(x) and then we will set it equal to
.
hg(x) =
which simplifies to
. Now set that equal to
:
and get everything on the same side and factor:
. Factor by grouping:
and factor out what's common in each set of ( ):
which factors out to
. But
factors somoe to:
(x + 1)(x - 1)(x - 1) = 0 So the solutions for this are
x = -1, 1
The "relative frequency" is
(number of times a blue marble came out)
divided by
(total number of trials before everybody got bored and quit) .
-- The relative frequency of blue was (20/60) = (33 and 1/3) % .
(Even though 38.5% of the marbles in the jar are blue,
they didn't get picked that often.)
-- The relative frequency of green was (18/60) = 30 % .
(Even though only 26.9% of the marbles in the jar are green,
they got picked more often than that.)
-- The relative frequency of red was (22/60) = (36 and 2/3) % .
(Even though 42.3% of the marbles in the jar are red,
they didn't get picked that often.)
Answer:
11.8 in.
Step-by-step explanation: