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N76 [4]
2 years ago
15

Help me with Question 4

Mathematics
2 answers:
ruslelena [56]2 years ago
7 0

Answer:

a

Step-by-step explanation:

Natali [406]2 years ago
6 0

Answer:

A

Step-by-step explanation:

This is cause the phrase two thirds refrences as two of three which is a fraction.

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Tickets to the concert were 2.50 for adults and 1.00 for students. 1,200 was collected and 750 tickets were sold.
Minchanka [31]

Answer:

I'm assuming you want to know the amount of child and adult tickets sold. 450 student tickets were sol, and 300 adult tickets.

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

3 0
3 years ago
For some postive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770. The value of Z is
Talja [164]

Answer:

1.16

Step-by-step explanation:

Given that;

For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.

This implies that:

P(0<Z<z) = 0.3770

P(Z < z)-P(Z < 0) = 0.3770

P(Z < z) = 0.3770 + P(Z < 0)

From the standard normal tables , P(Z < 0)  =0.5

P(Z < z) = 0.3770 + 0.5

P(Z < z) =  0.877

SO to determine the value of z for which it is equal to 0.877, we look at the

table of standard normal distribution and locate the probability value of 0.8770. we advance to the  left until the first column is reached, we see that the value was 1.1.  similarly, we did the same in the  upward direction until the top row is reached, the value was 0.06.  The intersection of the row and column values gives the area to the two tail of z.   (i.e 1.1 + 0.06 =1.16)

therefore, P(Z ≤ 1.16 ) = 0.877

8 0
3 years ago
Solve for x. This figure is a parallelogram
stich3 [128]

Answer:

x=9

Step-by-step explanation:

Since you don't have that much information, you have to assume line HE is congruent to line GF, so now you have an equation that looks like this:  23=x+14.  Now you subtract 14 from both sides giving you 9=x, and since you cannot simplify even further, that is your answer

3 0
3 years ago
PLEASE HELP Solve |10x + 15| &gt;= 105
yan [13]
|10x + 15| \geq 105\\&#10; 5|2x + 3| \geq 105\\&#10;|2x+3|\geq21\\&#10;2x+3\geq21 \vee 2x+3\leq-21\\&#10;2x\geq 18\vee2x\leq-24\\&#10;x\geq9 \vee x\leq-12\\&#10;x\in(-\infty,-12\rangle\cup\langle9,\infty)
8 0
3 years ago
For what values of t on the interval [0, 21 ]is the instantaneous velocity positive​ (the projectile moves​ upward)?
OLEGan [10]

Answer:

0 <=t<=21

Step-by-step explanation:

Projectile is Moving upwards on an interval of (0 to 21), if we plot Velocity vs Time and denote positive y-axis above 0 and negative y-axis below  0(for velocity), then from 0 to 21 t projectile is moving upwards and has positive velocity, when the projectile reaches the top of it's motion and returns back down to ground it's velocity is negative and is plotted below the y =0 (note that is for t > 21).

hence for the interval 0 <=t <=21 the instantaneous velocity is positive (Note, instantaneous velocity is also the derivative of the velocity or the slope ).

8 0
2 years ago
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