Answer:
75
Step-by-step explanation:
180-30=150
150/2=75
If 4=2^2
8=2^3
(2^)2x+10=(2^)6x
(2^)6x-(2^)2x=10
(2^)2x×7=10, where x has no real value
What options can you choose from? I guess it would be something like the medicine works or the medicine is not a placebo
Answer:
The standard issue license plates that can be produced if there are no restrictions on the letters and numbers = 175760000
Step-by-step explanation:
If there are no restrictions, all numbers and letters are available to be used then. And with no restrictions, every number or letter can appear more than once.
There are 7 spaces available; 3 spaces for letters, 4 spaces for numbers
The different combination of letters and numbers then becomes,
26 × 26 × 26 × 10 × 10 × 10 × 10
This is because, all 26 letters (A to Z) can occupy the first space, the second space and the third space. And all 10 digits (0 to 9) can occupy the fourth space, the fifth space, the sixth space and the seventh space.
So, the standard issue license plates that can be produced if there are no restrictions on the letters and numbers = 26 × 26 × 26 × 10 × 10 × 10 × 10 = 175760000 different standard issue license plates.
D midpoint of EC -----------------> FD parallel to AC and FD=AC/2=14/2=7
<span>2-EB=EA E midpoint of AB </span>
<span>DB=DC D midpoint BC ...............> ED=AC/2=2 </span>
<span>3-T midpoint of SR </span>
<span>U midpoint of QR ---------> TU = QS/2 </span>
<span>QS=2 TU = 4.4 </span>
<span>4- The same steps SR=2 UV=9 </span>
<span>5-N midpoint of KM </span>
<span>O midpoint of ML </span>
<span>* NO parallel to Kl</span>
