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Sloan [31]
2 years ago
10

ABCD and EFII GĦ. Use the figure above to find the value of each angle.

Mathematics
1 answer:
Marta_Voda [28]2 years ago
5 0

Hope these help but i wrote all of it out with all its geometrical reasons

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Simplify 7 square root 2535
JulijaS [17]
 7*sqrt(3*5*13^2) = 91*sqrt(15) = 91*3.872983346 = 352.4414845<span>
</span>
5 0
3 years ago
Read 2 more answers
9. Tobias ran 3 miles. How many millimeters did he run? (1 mile = 1,610 meters)
Gekata [30.6K]

Welcome to Brainly! I'm happy to help!

We see that there are 1,610 meters in a mile. However, we are looking for millimeters, not meters. But, knowing the meters will help us out.

A millimeter is a very small measurement. There are 1,000 millimeters in 1 meter. A meter is much larger. So, if we want to convert 1,610 meters to millimeters, there are going to be way more millimeters because they are so minute.

This means that we will have to multiply. We know that there are 1,000 millimeters in 1 meter, so if we multiply our meters by 1,000 (which is basically just adding 3 zeros), we will get the number of millimeters in one mile!

1,610×1,000=1,610,000 (one million six hundred and ten thousand!)

Don't forget that we are looking for 3 miles though, so we can take the number of millimeters in one mile and multiply by three.

1,610,000×3=4,830,000 (four million eight hundred and thirty thousand!)

So, Tobias ran 4,830,000 millimeters!

Have a wonderful day and keep on learning! :D

7 0
3 years ago
Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(−2, 1) and Q(8, 9)
IrinaK [193]

Answer:

Equation of the circle   (x-3)²+(y-5)²=(6.4)²

                             x² -6x +9 +y² -10y +25 = 40.96

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given endpoints of diameter P(−2, 1) and Q(8, 9)

Centre of circle = midpoint of diameter

                   Centre = (\frac{-2+8}{2} ,\frac{1+9}{2} )

               Centre (h, k) = (3 , 5)

<u><em>Step(ii):-</em></u>

The distance of two end points

PQ = \sqrt{(x_{2}-x_{1} )^{2} +(y_{2} -y_{1} )^{2}  }

PQ= \sqrt{(8+2 )^{2} +(8 )^{2}  }

PQ = √164 = 12.8

Diameter    d = 2r

                 radius r = d/2

                Radius r = 6.4

<u><em>Final answer:-</em></u>

Equation of the circle  

                    (x-h)²+(y-k)² = r²

                   (x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

x² -6x  +y² -10y  = 40.96-34

x² -6x  +y² -10y -7= 0

4 0
3 years ago
Round 3308.89 to the nearest australian dollar
const2013 [10]
Round 3308.89 to the nearest Australian dollar - $4336 AUD .
3 0
3 years ago
In a particular​ year, a total of 44,064 students studied in two of the most popular host countries when traveling abroad. If 83
lorasvet [3.4K]

Answer:

The answer would be 35066 :)

Step-by-step explanation:

(y+5554) + y = 64578

Combine like terms

2y = 64578-5554

2y = 59024

y = 29512

x = 29512 + 5554 = 35066

6 0
2 years ago
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