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Stels [109]
4 years ago
8

If OB= 17 and AB = 30, then OR =

Mathematics
2 answers:
Novay_Z [31]4 years ago
6 0
The correct answer is 8
Because
In triangle ORB
OR=(OB^2-RB^2)^1/2
OR=(17^2-15^2)^1/2
OR=(289-225)^1/2
OR=(64)^1/2
OR=8
RB=AB/2 so I kept its value 15 and ^1/2 refers to square root
nordsb [41]4 years ago
3 0

Answer:

Option A.

Step-by-step explanation:

Given information: OB= 17 and AB = 30

If a line is perpendicular to a chord of a circle and passes through the centre of the circle, then it bisects that chord.

Using this definition we can say that point R is the midpoint of AB.

RB=\dfrac{AB}{2}

RB=\dfrac{30}{2}

RB=15

According to the Pythagoras theorem, in a right angle triangle

hypotenuse^2=base^2+perpendicular^2

Using Pythagoras theorem in triangle ORB,

OB^2=RB^2+OR^2

(17)^2=(15)^2+OR^2

289=225+OR^2

289-225=OR^2

64=OR^2

Taking square root on both sides.

\sqrt{64}=OR

8=OR

The val;ue of OR is 8 units.

Therefore, the correct option is A.

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g100num [7]

52 ten cent coins, and you have 36 five cent coins.

Their sum is 700 cents which is equal to 7 dollars.

6 0
3 years ago
5x - 2y = 15 2x + 4y = 12 According to the strategy you learned in this lesson, what is the best first step in solving the syste
Genrish500 [490]
The answer to the question

3 0
3 years ago
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8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

7 0
3 years ago
Nine fever than half a number is five more than four times the number
gogolik [260]
9-1a/2 = 5+4a
-5         -5

4-1a/2 = 4a
  +1a/2   +1a/2

4 = 9a/2
*2   *2

8 = 9a
/9   /9

8/9 = a

HOPE THIS HELPS!!!
5 0
3 years ago
HELP ANYONE TIMEDD
zhenek [66]
The correct answer is 2/3 i believe <span />
6 0
4 years ago
Read 2 more answers
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