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Nonamiya [84]
4 years ago
12

What error did Clyde make? And what is the correct simplified form

Mathematics
2 answers:
Ipatiy [6.2K]4 years ago
8 0

Clyde should have applied the power of a power rule and multiplied the exponents instead of adding them. The simplified form should be j to the 16 th power.

romanna [79]4 years ago
3 0

Answer:

Clyde added -8+(-2), your supposed to multiply -8*(-2) the answer is j^16

Step-by-step explanation:

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Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex
siniylev [52]

Answer:

\large \boxed{\sf \ \ \ p=-11 \ \ \ }

Step-by-step explanation:

Hello,

\alpha \text{ and } \beta \text{ are the roots of the following equation}

   2x^2+6x-7=p

It means that

   2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\

And we know that

\alpha= 2\cdot \beta

So we got two equations

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I assume that we are after two different roots so the solution for p is p=-11

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So a quadratic equation with the expected roots  is

x(x-1)=x^2-x

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
3 years ago
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