All categories

2 years ago

Help help help help help

Mathematics

1 answer:

Nesterboy [21]2 years ago

8 0

Answer:

$b = \sqrt{65}$

Step-by-step explanation:

${b}^{2} + {4}^{2} = {9}^{2} \\ {b}^{2} + 16 = 81 \\ {b}^{2} = 81 - 16 \\ {b}^{2} = 65 \\ b = \sqrt{65}$

I hope I helped you^_^

You might be interested in

Write a story that can be represented by the equation y=x+1/4x

makvit [3.9K]

This question is pretty much asking: Write a story that can be represented by the equation y=1.25x.

So, how about this one: Lily's mom tells Lily to clean up her toys. Lily puts toys away at a rate of one toy per every 1.25 seconds.

That's it, simple as that :P

(Sorry if it wasn't too helpful.)

7 0

3 years ago

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago

Which is smaller,two-thirds of 27 or two-fifths of 20?

shtirl [24]

" of " means multiply

2/3(27) = 54/3 = 18
2/5(20) = 40/5 = 8

so 2/5 of 20 is smaller

7 0

3 years ago

Ving tomation.

jek_recluse [69]

Man i don’t know
i really donttt

3 0

2 years ago

rank has a circular garden. The area of the garden is 100 ft2. What is the approximate distance from the edge of Frank’s garden

Ray Of Light [21]

It is given that the area of the circular garden = 100 $ft^2$

Area of circle with radius 'r' = $\pi r^2$

We have to determine the approximate distance from the edge of Frank’s garden to the center of the garden, that means we have to determine the radius of the circular garden.

Since, area of circular garden = 100

$\pi r^2 = 100$