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3 years ago

13

I am very bad at math and need help with is 15÷2681

2 answers:

NNADVOKAT [17]3 years ago

4 0

if you use a calculator the answer is 0.00559493

soldi70 [24.7K]3 years ago

3 0

you can rounded the number to 0.006

Hope i helped!! :)

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Lowest common multiple of 20 and 54

Ivahew [28]

The LCM is 540 because 54X10=540 which 20 goes into

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3 years ago

Examine the diagram at right. The smaller triangle (inside of the larger triangle) is similar to larger triangle. How can you so

olchik [2.2K]

As the exercise says, the triangles are similar. So, we can set up proportions between correspondent sides.

In order to solve for x we can set up the proportion between the horizontal and vertical sides:

$28\div 11.2 = 27+x \div x$

Solving this proportion for x implies $x=18$

Now you can solve for m and p using the pythagorean theorem, because both triangles are right:

$m = \sqrt{18^2+11.2^2} =21.2$

Then, we know that the hypothenuse of the big triangle is m+p, so we have

$m+p=\sqrt{(18+27)^2+28^2} = 53$

which implies

$p = 53-p = 53-21.2=31.8$

6 0

3 years ago

Base = 5 ft Height= 3.5 ft what is the area

Advocard [28]

Answer:

the area is 17.5 ft if the shape is a square/rectangle

the area is 8.75 ft if the shape is a triangle

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Evaluate the line integral, where C is the given curve. C sin(x) dx + cos(y) dy, where C consists of the top half of the circle

kenny6666 [7]

Parameterize the circular part of $C$ (call it $C_1$ ) by

$x=4\cos t$

$y=4\sin t$

wih $0\le t\le\pi$ , and the linear part (call it $C_2$ ) by

$x=-4-t$

$y=4t$

with $0\le t\le1$ .

Then

$\displaystyle\int_C\sin x\,\mathrm dx+\cos y\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}\sin x\,\mathrm dx+\cos y\,\mathrm dy$

$=\displaystyle\int_0^\pi(-4\sin t\sin(4\cos t)+4\cos t\cos(4\sin t))\,\mathrm dt+\int_0^1(-\sin(-4-t)+\cos4t)\,\mathrm dt$

$=0+\displaystyle\int_0^1(\sin(t+4)+\cos4t)\,\mathrm dt$

$=\cos4-\cos5+\dfrac{\sin4}4$

7 0

3 years ago

Tessa said that the combined length of all 5 of her fingers on one hand should be less that 5 times the index finger. Tessa had

Alekssandra [29.7K]

Answer: 5F < 5( X + x )

Step-by-step explanation:

Let each finger = F and

The index finger = X

The shortest index finger = x

the combined length of all 5 of her fingers on one hand should be less than 5 times the length of index finger

From the statement above, we get

5F < 5X

Tessa add the second shortest index finger.

That is

5F < 5( X +x)

7 0

3 years ago