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Rainbow [258]
3 years ago
6

Find the slope of each line. А B с A) A B) C)

Mathematics
2 answers:
Vladimir79 [104]3 years ago
6 0

Answer:

A=b B=C C=A

Step-by-step explanation:

cluponka [151]3 years ago
5 0

Answer: Ola

Step-by-step explanation:

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Eric buys two plants. One plant is 4 inches tall and grows 2 of an inch per week. Another plant is 3 inches tall and grows
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It’s Abe beacuse it grew 7 inch week and 4 tall 2 week.
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Simplify the expression.<br> (4a- 80 - 4a2) + (7a3 - 7 - 6a)
allsm [11]

Answer:

the answer should be 7a^3-4a^2-2a-87

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3 years ago
Eight more than the quotient of a number and 4 equals 5
Lady bird [3.3K]
Well we can put that word problem into a equation so, 8+x/4=5. Now what I would do is move the 8 to the other side, and since it moved to the other side it becomes a -8 so now we have x/4 = -3. Now I would multiply both side by 4 to get x = -12

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3 years ago
kayla and Jane helped Mr.John fit kids in the auditorium. There was 603 kids,and each row can fit 31 kids. How many rows do they
olga2289 [7]

Answer:

Around 19 rows

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4 0
2 years ago
Suppose that a company prints baseball cards. They claim that 30% of the cards feature rookies, 60% feature veterans, and 10% fe
liraira [26]

Answer:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

Step-by-step explanation:

On this case we need to apply a Chi squared goodness of fit test, and the correct system of hypothesis would be:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

And in order to test it we need to have observed and expected values. On this case we  can calculate the Expected values like this

E_{rookies}=50*0.3=15

E_{veterans}=50*0.6=30

E_{All stars}=50*0.1=5

The observed values are not provided. The statistic on this case is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i) -E_i}{E_i}

And this statistic follows a chi square distribution with k-1 degrees of freedom on this case k=3, since we have 3 groups.

We can calculate the p valu like this:

P(\chi^2 > \chi^2_{calculated})=p_v

And if the p value it's higher than the significance level we FAIL to reject the null hypothesis. In other case we reject the null hypothesis.

5 0
3 years ago
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