Answer:
0.5 inch on the drawing
Step-by-step explanation:
The following information is missing:
<em>The scale factor of the drawing to the actual flag is represented by the ratio 1:18. </em>
This scale factor means that 1 inch on the drawing are equivalent to 18 inches o
n the actual flag. We want to know the height on the drawing, given that a height of 9 inches is drawn on the actual flag. The following proportion must be satisfied:
1 inch on the drawing / x inch on the drawing = 18 inches o
n the actual flag / 9 inches o
n the actual flag
x = 9/18 = 0.5 inch on the drawing
Formula: sqr((x2-x1)^2 + (y2-y1)^2)
sqr((-4-2)^2 + (-7+2)^2)
sqr(-6)^2 + (-5)^2)
sqr(36)+(25)) = sqr(61)
The answer is A. sqr(61)
Answer: The correct option is fourth, i.e., 1935 cm³.
Explanation:
It is given that the vase is 30 cm tall and the hexagon base has an area of 64.5 cm².
The area of a hexagon base is,
![A=\frac{3\sqrt{3}} {2}a^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B3%5Csqrt%7B3%7D%7D%20%7B2%7Da%5E2)
Where, a is the side length.
The volume of the a hexagon glass is,
![V=\frac{3\sqrt{3}} {2}a^2\times h](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B3%5Csqrt%7B3%7D%7D%20%7B2%7Da%5E2%5Ctimes%20h)
![V=A\times h](https://tex.z-dn.net/?f=V%3DA%5Ctimes%20h)
Where, A is area of base of hexagon and h is height of the hexagon glass.
![V=64.5\times 30](https://tex.z-dn.net/?f=V%3D64.5%5Ctimes%2030)
![V=1935](https://tex.z-dn.net/?f=V%3D1935)
Therefore the volume of the glass is 1935 cm³ and the glass can hold 1935 cm³ water. So, fourth option is correct.
The anwser is ten because the number i saw is 14 estimate is ten.
Answer:
x=2+
or x= 2-![\sqrt[]{2}\\](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B2%7D%5C%5C)
Step-by-step explanation: