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3 years ago

EUR

Mathematics

1 answer:

Georgia [21]3 years ago

3 0

Answer:

22 Miles

Step-by-step explanation:

Assuming that the friend's house is in the direction of the movie theater, if you take 10 then subtract the two miles before the pit stop, you get 8. Then subtract 30 to get -22 (the negative only means she went too far). That means she is 22 miles away from the movie theater. Hope this helps!

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Identify the volume of the composite figure. HELP PLEASE!!

Ilya [14]

Answer:

Vol. of the composite figure is 189 m³

Step-by-step explanation:

Find the volume of the larger figure by mult. together its 3 dimensions:

V = (9 m)(8 m)(3 m) = 216 m³.

Next, find the volume of the "notch," which is (3 m)³, or 27 m³.

Finally, subtract the "notch" volume from the 216 m³ volume found earlier:

216 m³ - 27 m³ = 189 m³

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You ride your skateboard to school and tell all your friends you rode at a speed of 25 mph. They know this cannot he true becaus

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The distance between your house and school and how long it took you to get there

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3 years ago

Model 2.4 divided by 8

spin [16.1K]

2.4 ÷ 8= 0.3
The decimal stays the same.

Hoped this helped.

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3 years ago

Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t

andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ. $e^{-\lambda.x}$

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - $e^{-\lambda.x}$

(a) Probability of distance at most 100m, with λ = 0.0143:

F(100) = 1 - $e^{-0.0143.100}$

F(100) = 0.76

Probability of distance at most 200:

F(200) = 1 - $e^{-0.0143.200}$

F(200) = 0.94

Probability of distance between 100 and 200:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = $\frac{1}{\lambda}$

E(X) = $\frac{1}{0.0143}$

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = $\sqrt{\frac{1}{\lambda^{2}} }$

σ = $\sqrt{\frac{1}{0.0143^{2}} }$

σ = 69.93

Distance exceeds the mean distance by more than 2σ:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - $e^{-0.0143*209.79}$ )

P(X > 209.79) = 0.0503

P(X≤m) = 0.5

$\int\limits^m_0 f({x}) \, dx$ = 0.5

$\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx$ = 0.5

$\lambda.\frac{e^{-\lambda.x}}{-\lambda}$ = $-e^{-\lambda.x} + e^{0}$

$1 - e^{-\lambda.m}$ = 0.5

$-e^{-\lambda.m}$ = - 0.5

ln( $e^{-0.0143.m}$ ) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

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Triangle B can be proven congruent

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3 years ago

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