Let point A be
and point B 

Use the point-slope formula and whichever point you want as , in this case I'll use

If you list all the common factors, (1,2,3,6), you see the highest common factor is 6
A quadratic equation has the general form
of: <span>
y=ax² + bx + c
It can be converted to the vertex form in order
to determine the vertex of the parabola. It has the standard form of:
y = a(x+h)² - k
This can be done by completing a square. The steps are as follows:
</span><span>y = 3x2 + 9x – 18
</span>y = 3(x2 <span>+ 3x) – 18
</span>y + 27/4= 3(x2 <span>+ 3x+ 9/4) – 18
</span>y = 3(x2 + 3/2)^2 – 99<span>/4
</span>
Therefore, the first step is to group terms with the variable x and factoring out the coefficient of x^2.
Answer:
<u>Angle 1</u>= 180 - 110 = 70 (straight angle)
<u>Angle 2</u> = 180 - 115 =65 (straight angle)
<u>Angle 3</u>= angle 2 =65 (corresponding alternating angles)
<u>Angle 4</u> =180 - angle3 = 180 - 65 = 115 (straight angle)
<u>Angle 5</u> = 180 - angle 1 - angle 3= 180 - 70 - 65 = 45 (sum of triangle angles is equal to 180)
<u>Angle </u><u>6</u> = angle 5= 45 ( interior alternating angles)
<u>Angle</u><u> </u><u>7</u><u> </u>= angle 6= 45 (vertical opposite angles)
<h3>

</h3>
Answer:
6? If its a squared machine than it is 6 bc 6 squared is 36. sorry if it is wrong.
Step-by-step explanation: