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3 years ago

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1 answer:

Natali5045456 [20]3 years ago

6 0

(NH4)2CO3(s) ⇄ 2NH3(g) + CO2(g) + H2O (g)

The effect that adding water (H2O) have in reaction above is that The concentration of the product would decrease, and the concentration of reactant would increase. (answer C)

<u><em>Explanation</em></u>

If the concentration of one substance is changed, the equilibrium shift to minimize the effect of that change.

H2O in reaction above is a product.

Increase of water (H2O) concentration will led to the shift of equilibrium to the left ( reactant side) .The concentration of reactant increase as that of product decrease.

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A non-reflective coating that has a thickness of 198 nm (n = 1.45) is deposited on top of a substrate of glass (n = 1.50). What

spin [16.1K]

Answer:

The wavelength is $\lambda_ 1 = 574.2 nm$

Explanation:

From the question we are told that

The thickness is $t = 198 nm = 198 *10^{-9 }\ m$

The refractive index of the non-reflective coating is $n_m = 1.45$

The refractive index of glass is $n_g = 1.50$

Generally the condition for destructive interference is mathematically represented as

$2 * n_m * t * cos (\theta) = n * \lambda$

Where $\thata$ $\theta$ is the angle of refraction which is 0° when the light is strongly transmitted

and n is the order maximum interference

so

$\lambda = \frac{2 * n * t * cos (\theta )}{n}$

at the point n = 1

$\lambda _1 = \frac{2 * 1.45 * 198*10^{-9} * cos (0 )}{1}$

$\lambda_1 = 574.2 *10^{-9}$

$\lambda_1 = 574.2 nm$

at n =2

$\lambda _2 = \frac{\lambda _1 }{2}$

$\lambda _2 = \frac{574.2*10^{-9} }{2}$

$\lambda _2 = 2.87 1 *10^{-9} \ m$

$\lambda _2 = 287. 1 nm$

Now we know that the wavelength range of visible light is between

$390 \ nm \to 700 \ nm$

So the wavelength of visible light that is been transmitted is

$\lambda_ 1 = 574.2 nm$

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4 years ago

Steel is an alloy of ___ One of the main reasons steel is used more widely than iron is because it’s___ than iron.

Tresset [83]

Iron, Stronger than iron

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4 years ago

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While getting buff at the gym you lift a bunch of weights applying 1000N of force to lift them from the ground to a height of 2m

slega [8]

A. 2000 J............

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3 years ago

A 110 kg ice hockey player skates at 3.0 m/s toward a railing at the edge of the ice and then stops himself by grasping the rail

velikii [3]

Answer:

Δ KE = -495 J

Explanation:

given,

mass of the ice hockey player = 110 Kg

initial speed = 3 m/s

final speed = 0 m/s

distance, d = 0.3 m

change in kinetic energy

$\Delta K E = \dfrac{1}{2}mv_f^2 - \dfrac{1}{2}mv_i^2$

$\Delta K E = \dfrac{1}{2}mv(0)^2 - \dfrac{1}{2}\times 110\times 3^2$

Δ KE = -495 J

Hence, the change in kinetic energy is equal to Δ KE = -495 J

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3 years ago

The maximum current output of a 60 ω circuit is 11 A. What is the rms voltage of the circuit?

Scilla [17]

Answer:

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Explanation:

I dont know the anwser to that one

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3 years ago