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tresset_1 [31]
2 years ago
13

Which of the following are simple machines? Select all that apply.

Physics
2 answers:
valentinak56 [21]2 years ago
7 0

where aee the options

for eg .. of simple machine

wheel , screw etc..

scoundrel [369]2 years ago
5 0

Answer:

where is option

you only say choose that following select apply

Explanation:

please give option

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A 38.5 kg man is in an elevator
Vika [28.1K]
I’m not too sure but I think it’s 8,91 m/s2
3 0
3 years ago
A 30.0 kg dolphin decelerates from 12.0 to 7.00 m/s in 2.60 s to join another dolphin in play. What average force (in N) was exe
Crazy boy [7]

Answer:

Force is 57.69 N to the opposite direction of motion of dolphin.

Explanation:

We have force is the product of mass and acceleration.

That is    

                 Force = Mass x Acceleration

                         F = ma

Mass of dolphin, m = 30 kg

We have equation of motion, v = u + at

Final velocity, v = 7 m/s

Initial velocity, u = 12 m/s

Time, t = 2.60 s

Substituting

                   7 = 12 + a x 2.6

                    a = -1.92 m/s²

Force,   F = 30 x -1.92 = -57.69 N

So the force is 57.69 N to the opposite direction of motion of dolphin.

7 0
3 years ago
12. A diagram of the Earth revolving around the sun shows that less direct sunlight is reaching the Northern Hemisphere than the
Natali [406]
The northern hemisphere season is summer
5 0
3 years ago
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The distance between two cities is 144km; it takes me 3 hours to travel between these cities. What average speed did I travel at
alexandr402 [8]

Answer:

48km/hr

Explanation:

Check attachment

3 0
3 years ago
A coil is connected in series with a 19.0 kΩ resistor. An ideal 50.0 V battery is applied across the two devices, and the curren
Gre4nikov [31]

Answer:

inductance of the coil 29.3767  H

Explanation:

given data

resistor R =  19.0 kΩ = 19 × 10³ Ω

potential applied V  = 50.0 V

current I = 2.20 mA  =  2.20 × 10^{-3} A

time t = 2.80 ms = 2.80 × 10^{-3} s

solution

we know for maximum current in circuit that is

current = V ÷ R   .........1

current =  \frac{50}{19\times 10^3}

current = 2.63 × 10^{-3} A

so at time t = 0

t = -\frac{L}{R} ln(1-\frac{I_f}{I_{max}})  

2.80 \times 10^{-3} = -\frac{L}{19\times 10^3} ln(1-\frac{2.20\times 10^{-3}}{2.63\times 10^{-3}}})  

L = 29.3767

3 0
3 years ago
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