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2 years ago

Which of the following are simple machines? Select all that apply.

Physics

2 answers:

valentinak56 [21]2 years ago

7 0

where aee the options

for eg .. of simple machine

wheel , screw etc..

scoundrel [369]2 years ago

5 0

Answer:

where is option

you only say choose that following select apply

Explanation:

please give option

You might be interested in

What is mass times acceleration?

frozen [14]

Answer:

Force

Explanation:

The mass of an object is the quantity of matter it contains. It is measured in kilograms.

Acceleration is the ratio of the change in the velocity of an object to the change in time. It is measured in m/ $s^{2}$ .

When the mass of an object is multiplied with its acceleration, this gives the average force applied on the object. As force is defined as agent that can change the state of an object.

i.e F = m × a

where F is the force, m is the mass of the object and a its acceleration.

The two major classes of force are; contact force and field force.

6 0

3 years ago

It is friction that provides the force for a car to accelerate, so for high-performance cars the factor that limits acceleration

bearhunter [10]

Answer:

About 12 seconds

Explanation:

6 0

3 years ago

3. A 2kg wooden block whose initial speed is 3 m/s slides on a smooth floor for 2 meters before it comes to a

serious [3.7K]

Answer:

Calculating Coefficient of friction is 0.229.

Force is 4.5 N that keep the block moving at a constant speed.

Explanation:

We know that speed expression is as $\mathrm{V}^{2}=\mathrm{V}_{\mathrm{i}}^{2}+2 . \mathrm{a} . \Delta \mathrm{s}$ .

Where, ${V}_{i}$ is initial speed, V is final speed, ∆s displacement and a acceleration.

Given that,

${V}_{i}$ =3 m/s, V = 0 m/s, and ∆s = 2 m

Substitute the values in the above formula,

$0=3^{2}-2 \times 2 \times a$

0 = 9 - 4a

4a = 9

$a=2.25 \mathrm{m} / \mathrm{s}^{2}$

$a=2.25 \mathrm{m} / \mathrm{s}^{2}$ is the acceleration.

Calculating Coefficient of friction:

$\mathrm{F}=\mathrm{m} \times \mathrm{a}$

$\mathrm{F}=\mu \times \mathrm{m} \times \mathrm{g}$

Compare the above equation

$\mu \times m \times g=m \times a$

Cancel "m" common term in both L.H.S and R.H.S

$\text { Equation becomes, } \mu \times g=a$

$\text { Coefficient of friction } \mu=\frac{a}{g}$

$\mathrm{g} \text { on earth surface }=9.8 \mathrm{m} / \mathrm{s}^{2}$

$\mu=\frac{2.25}{9.8}$

$\mu=0.229$

Hence coefficient of friction is 0.229.

calculating force:

$\text { We know that } \mathrm{F}=\mathrm{m} \times \mathrm{a}$

$\mathrm{F}=2 \times 2.25 \quad(\mathrm{m}=2 \mathrm{kg} \text { given })$

F = 4.5 N

Therefore, the force would be <u>4.5 N</u> to keep the block moving at a constant speed across the floor.

7 0

3 years ago

After pushing away from each other, two objects have equal but opposite momentum. Which of the following is true for the total m

weqwewe [10]

I think the answer is B

5 0

3 years ago

Si se tiene un gato hidráulico y se aplica una fuerza en el Area 1, se refleja otra fuerza en el Area 2, teniendo en cuenta la s

iren [92.7K]

Answer:

the forces are proportional to their areas of application

Explanation:

In a hydraulic jack, Pascal's principle is used, that the pressure in an incompressible liquid is the same at the same height, whereby the pressure on both sides of the jack are the same

P₁ = P₂

the pressure is defined by

P = F / A

we substitute

$\frac{F_1}{A_1} = \frac{F_2}{A_2}$

F₂ = $\frac{A_2}{A_1} \ F_1$

therefore the force is F₂> F₁

Therefore the forces are proportional to their areas of application

7 0

3 years ago