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Verdich [7]
3 years ago
14

PLEASE HELP!!!!!

Mathematics
1 answer:
shutvik [7]3 years ago
5 0

c. 0 ≤ x ≤ 30,000

_____________

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When x = 1/2, what is the value of 8x-3/x ?
Free_Kalibri [48]
Answer choice G.

1. Plug in 1/2 for x
2. Evaluate with PEMDAS
3. Solve

7 0
3 years ago
Goran runs 6 miles in 57 minutes how many miles does he run per minute?
Morgarella [4.7K]
57/6 = 1/x
57 = 6x
x = 0.11 miles per minute
4 0
3 years ago
Saturn’s rings span up to about (7.5 · 10-1) of the distance between the Earth and its moons. If Saturn’s rings span up to (2.82
RUDIKE [14]
2.82 × 10^5 = (7.5×10^-1) × Length between the earth and the moon
Length between the earth and the moon = (2.82×10^5)÷(7.5×10^-1)                                                                     = 376000                                                                     = 3.76×10^5
i think this is correct hope it helps. 
7 0
3 years ago
Read 2 more answers
How many squares do you see?
melamori03 [73]

Answer:

<h3>.There are 36 squares........</h3>
6 0
3 years ago
Read 2 more answers
Evaluate................
wolverine [178]

Answer:

h(8q²-2q) = 56q² -10q

k(2q²+3q) = 16q² +31q

Step-by-step explanation:

1. Replace x in the function definition with the function's argument, then simplify.

h(x) = 7x +4q

h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q

__

2. Same as the first problem.

k(x) = 8x +7q

k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q

_____

Comment on the problem

In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...

h(8q² -2q) = 56q² -14q +4z

and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.

In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.

7 0
4 years ago
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