Answer:
Yes.
Step-by-step explanation:
Yes.
Assuming a, b and c are integers (not = 0)
a/b + b/c
= (ac + b^2) / bc which is a rational number.
To justify the yearly membership, you want to pay at least the same amount as a no-membership purchase, otherwise you would be losing money by purchasing a yearly membership. So set the no-membership cost equal to the yearly membership cost and solve.
no-membership costs $2 per day for swimming and $5 per day for aerobic, in other words, $7 per day. So if we let d = number of days, our cost can be calculated by "7d"
a yearly membership costs $200 plus $3 per day, or in other words, "200 + 3d"
Set them equal to each other and solve:
7d = 200 + 3d
4d = 200
d = 50
So you would need to attend the classes for at least 50 days to justify a yearly membership. I hope that helps!
I hope this helps you
f(8)=2.8+5=21
g(8)=3.8+6=30
f-g(8)=21-30= -9
Answer:
HCF×LCM=a×b
6×60=a×b
a×b=360
So the numbers are whose product is 360 and LCM is 60
These two numbers can be 6,60 or 12,30
