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icang [17]
3 years ago
15

15x -5 = 45 + 19 what is x

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
4 0

Answer:

x equals 4.6

Step-by-step explanation:

if u need explanation plz tell me so i can help

Dima020 [189]3 years ago
3 0

Answer:

x= 4.6

I need brainlist to level up please give it to me

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The number of customers waiting for gift-wrap service at a department store is an rv X with possible values 0, 1, 2, 3, 4 and co
julia-pushkina [17]

Answer:

P[X=3,Y=3] = 0.0416

Step-by-step explanation:

Solution:

- X is the RV denoting the no. of customers in line.

- Y is the sum of Customers C.

- Where no. of Customers C's to be summed is equal to the X value.

- Since both events are independent we have:

                         P[X=3,Y=3] = P[X=3]*P[Y=3/X=3]

              P[X=3].P[Y=3/X=3] = P[X=3]*P[C1+C2+C3=3/X=3]

        P[X=3]*P[C1+C2+C3=3/X=3] = P[X=3]*P[C1=1,C2=1,C3=1]        

              P[X=3]*P[C1=1,C2=1,C3=1]  = P[X=3]*(P[C=1]^3)

- Thus, we have:

                        P[X=3,Y=3] = P[X=3]*(P[C=1]^3) = 0.25*(0.55)^3

                        P[X=3,Y=3] = 0.0416

6 0
3 years ago
What are the endpoint coordinates for the midsegment of △PQR that is parallel to PQ¯¯¯¯¯?
andriy [413]

Answer:

M(x₄ ,y₄) = (-3.5 , 0.5)  and

N (x₅ ,y₅) = ( -1 , -0.5 )

Step-by-step explanation:

Let the endpoint coordinates for the mid segment of △PQR that is parallel to PQ be

M(x₄ ,y₄) and N(x₅ ,y₅) such that MN || PQ

point P( x₁ , y₁) ≡ ( -3 ,3 )

point Q( x₂ , y₂) ≡ (2 , 1 )

point R( x₂ , y₂) ≡ (-4 , -2)  

To Find:

M(x₄ ,y₄) = ?  and

N (x₅ ,y₅) = ?

Solution:

We have Mid Point Formula as

Mid\ point(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})

As M is the mid point of PR and N is the mid point of RQ so we will have

Mid\ pointM(x_{4} ,y_{4})=(\frac{x_{1}+x_{3} }{2}, \frac{y_{1}+y_{3} }{2})

Mid\ pointN(x_{5} ,y_{5})=(\frac{x_{2}+x_{3} }{2}, \frac{y_{2}+y_{3} }{2})

Substituting the given value in above equation we get

Mid\ pointM(x_{4} ,y_{4})=(\frac{-3+-4 }{2}, \frac{3+-2} }{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(\frac{-7} }{2}, \frac{1}{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(-3.5, 0.5)

Similarly,

Mid\ pointN(x_{5} ,y_{5})=(\frac{2+-4 }{2}, \frac{1+-2 }{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(\frac{-2 }{2}, \frac{-1}{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(-1, -0.5)

∴ M(x₄ ,y₄) = (-3.5 , 0.5)  and

  N (x₅ ,y₅) = ( -1 , -0.5 )

3 0
3 years ago
What is 3.116372 rounded to the nearest hundred thousandths place?
Neporo4naja [7]
Answer: 3.11637

Explanation: The hundred thousandths place is in the fifth place after the decimal. To avoid remembering this, you can simply note that the first place after the decimal is the tenths. You simply keep progressing as you would in whole numbers.

For example 10 becomes 100 when a zero is added. This zero is always added right beside the first zero and indicates the hundreds place.

Furthermore, the general rule for rounding is if the number after the preferred rounding place is 4 or less, the number remains the same. 5 or more means it goes up by one digit.
4 0
3 years ago
Read 2 more answers
When choosing a new class color, 90 students voted for crimson and 60 voted for royal blue. What percent of these students voted
neonofarm [45]
The percentage of students voted for colour crimson
=
\frac{90}{60 + 90} \times 100\%  \\  =  \frac{90}{150}  \times 100\%\\  =  \frac{9}{15} \times 100\% \\  = 60\%
hope it helps!
6 0
3 years ago
A circle is inscribed in a square with a side length of 144. If a point in the square is chosen at random, what is the probabili
____ [38]

Given :

A circle is inscribed in a square with a side length of 144.

So, radius of circle, r = 144/2 = 72 units.

To Find :

The probability that the point is inside the circle.

Solution :

Area of circle,

A_c = \pi r^2\\\\A_c = 3.14 \times 72^2\ units^2\\\\A_c = 16277.76 \ units^2

Area of square,

A_s = (2r)^2\\\\A_s = ( 2 \times 72)^2\ units^2\\\\A_s = 20736\ units^2

Now, probability is given by :

P = \dfrac{A_c}{A_s}\\\\P = \dfrac{16277.76}{20736}\\\\P = 0.785

Therefore, the probability that the point is inside the circle is 0.785 .

4 0
3 years ago
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