Considering that 1 kilogram is equal to 1000 grams and he made 9 loaves of bread using 30 grams each time, that equates to 270 grams of olives. 1000 - 270 = 730. Your answer is 730 grams of olives remain. Hope this helped.
Answer:
B
Step-by-step explanation:
This is all 1/3 of the number of times the experiment was tried to put in perspective john has 10 apples and he gives 3 away that's about 1/3 of the amount of apples
-22 = -2x + 9
-31 = -2x
-31/-2 = x
x = 15.5
Answer:
Answer is 6(3 d+2)
Step-by-step explanation:
It is given the expression as 18d+12
Let's find common factor by prime factoring the terms.
18 d =2*3*3*d
12= 2*2*3
Common factors for both terms are 2, 3.
So, G C F = 2*3=6
Take out 6 from both terms to factor further.
We do get 6(3 d+2)
9514 1404 393
Answer:
1a: x+3 = 5
1c: 6 = 2z
2b: x = 2
2d: 3 = z
3: the solutions make the hangars balance
Step-by-step explanation:
1. We can write the equations by listing the contents of the hangar and using an equal sign to show the balance between left side and right side. It can work well to put left side contents of the hangar on the left side of the equal sign.
A: x + 3 = 5
C: 1 + 1 + 1 + 1 + 1 + 1 = z + z simplifies to 6 = 2z
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2. B: We can subtract 3 from both sides of the hangar (and equation) to find the value of x.
(x +3) -3 = 5 -3
x = 2 . . . . . hangar balances with 2 on the right
D: We can divide both sides of the hangar by 2, splitting the content into two equal parts. Then one of those parts can be removed from each side.
2(3) = 2(z)
3 = z . . . . . . hangar balances with 3 on the left
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3. The found values will keep the hangar in balance when they are substituted for the corresponding variables.
A: 2 + 3 = 5
C: 1 + 1 + 1 + 1 + 1 + 1 = 3 + 3
