1) Given a (x) =6x+2 and b (x) = -8x -11

Can somebody who remembers how to do this answer all of these correclty thanks!!!!!!

Semenov [28]

Answer:

19) 7, 3, 2, -1, -8

20) 10, 2, 0, -3, -10

21) 3, 2, 1, 0, -1

22) -6, -7, -8, -9, -11

23) 7, 4, 0, -1, -2

Step-by-step explanation:

:))

6 0

3 years ago

The total output from a production system in one day is 900 units and the total labor necessary to produce the 900 units is 900

umka2103 [35]

Answer:

1.000

Step-by-step explanation:

Given that,

Total output from a production system in one day = 900 units

Total labor necessary to produce the 900 units = 900 hours

Productivity refers to the measure of efficiency of the inputs or labors for accomplishing a particular task. Productivity ratio is calculated by dividing the total output of a particular product to the total inputs employed in the production of that product.

Productivity ratio:

= Total output ÷ Total input

= 900 units ÷ 900 hours

= 1.000

6 0

3 years ago

find the slope of the curve y=x^2-2x-5 at the point P(2,5) by finding the limit of secant slopes through point P

Fynjy0 [20]

The point (2, 5) is not on the curve; probably you meant to say (2, -5)?

Consider an arbitrary point Q on the curve to the right of P, $(t,y(t))=(t,t^2-2t-5)$ , where $t>2$ . The slope of the secant line through P and Q is given by the difference quotient,

$\dfrac{(t^2-2t-5)-(-5)}{t-2}=\dfrac{t^2-2t}{t-2}=\dfrac{t(t-2)}{t-2}=t$

where we are allowed to simplify because $t\neq2$ .

Then the equation of the secant line is

$y-(-5)=t(x-2)\implies y=t(x-2)-5$

Taking the limit as $t\to2$ , we have

$\displaystyle\lim_{t\to2}t(x-2)-5=2(x-2)-5=2x-9$

so the slope of the line tangent to the curve at P as slope 2.

- - -

We can verify this with differentiation. Taking the derivative, we get

$\dfrac{\mathrm dy}{\mathrm dx}=2x-2$

and at $x=2$ , we get a slope of $2(2)-2=2$ , as expected.

4 0

3 years ago

Hey can anyone give me the answers to the questions that are blank

Brilliant_brown [7]

The value of the rate of change of the function is 14a + 7h

<h3>Rate of change of function</h3>

The rate of change of function is also known as the slope expressed according to the equation shown below;

f'(x) = f(a+h)-f(a)/h

Given the function below expressed as:

f(x) =1 + 7x^2

<u>Determine the function f(a)</u>

To determine the function, simply replace x with 'a" to have:

f(a) =1 + 7a^2

Determine the function f(a+h)

f(a+h) = 1 + 7(a+h)^2

f(a + h) = 1 + 7(a^2+2ah+h^2)

f(a + h) = 1 + 7a^2 + 14ah + 7h^2

To determine the rate of change

f'(x) = f(a+h)-f(a)/h

f'(x) = 1 + 7a^2 + 14ah + 7h^2 - 1 - 7a^2/h
f'(x) = + 14ah + 7h^2/h

f'(x) = 14a + 7h

Hence the value of the rate of change of the function is 14a + 7h

Learn more on rate of change here: brainly.com/question/8728504

#SPJ1

7 0

2 years ago

What are the types of roots of the equation below? x^4 - 81 = 0

blsea [12.9K]

Your answer is B, two complex roots and two real roots.

By factoring the original equation(which is a difference of two squares), you get:
$x^{4}-81=0\\(x^{2}-9)(x^{2}+9)=0$

Because first root is also a difference of two squares, it factors into x - 3 and x +3, your two real roots.
When you factor the second root, the roots are x - 3i and x + 3i.

To prove this, let's multiply them back together:
$[(x-3)(x+3)][(x-3i)(x+3i)]=0\\\\(x^{2}+3x-3x-9)(x^{2}+3xi-3xi-9i^{2})=0\\\\(x^{2}+0x-9)(x^{2}+0xi-9(-1))=0\\\\(x^{2}-9)(x^{2}+9)=0\\\\x^{4}+9x^{2}-9x^{2}-81=0\\\\x^{4}-81=0$

We reached the equation we started with, so that means that the roots are:
x + 3,
x - 3,
x + 3i, and
x - 3i,
two of which are real and two are complex.

7 0

3 years ago