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mina [271]
3 years ago
9

Where are the mail merge options located in Word 2016?

Computers and Technology
1 answer:
GarryVolchara [31]3 years ago
6 0

Answer:

Mailings Tab, Start Mail Merge group.

Explanation:

See attached picture.

You might be interested in
Identify the causes of configuration problems. (choose all that apply)
jolli1 [7]

Answer: The computer does not meet minimum requirements of the software program because too much energy gets put in it

Explanation:

Good luck

4 0
3 years ago
Read 2 more answers
2.Consider the following algorithm and A is a 2-D array of size ???? × ????: int any_equal(int n, int A[][]) { int i, j, k, m; f
Elis [28]

Answer:

(a) What is the best case time complexity of the algorithm (assuming n > 1)?

Answer: O(1)

(b) What is the worst case time complexity of the algorithm?

Answer: O(n^4)

Explanation:

(a) In the best case, the if condition will be true, the program will only run once and return so complexity of the algorithm is O(1) .

(b) In the worst case, the program will run n^4 times so complexity of the algorithm is O(n^4).

5 0
3 years ago
40 points to answer ALL
Kamila [148]

Answer:

#1 Use case diagram is one of them and its specific purpose is to gather system requirements and actors. Use case diagrams specify the events of a system and their flows.

#2 Software architecture refers to the high level structures of a software system and the discipline of creating such structures and systems. Each structure comprises software elements, relations among them, and properties of both elements and relations.

#3 Definition. A programming paradigm is a style, or “way,” of programming. Some languages make it easy to write in some paradigms but not others. Never use the phrase “programming language paradigm.” A paradigm is a way of doing something (like programming), not a concrete thing (like a language).

#4 Object-oriented programming (OOP) refers to a type of computer programming (software design) in which programmers define not only the data type of a data structure, but also the types of operations (functions) that can be applied to the data structure.

#5 Each flow chart is concerned with one particular process or system. ... Flow charts are an important tool for the improvement of processes. By providing a graphical representation, they help project teams to identify the different elements of a process and understand the interrelationships among the various steps.

#1 Programming style, also known as code style, is a set of rules or guidelines used when writing the source code for a computer program. It is often claimed that following a particular programming style will help programmers read and understand source code conforming to the style, and help to avoid introducing errors.

#2 Version control is a system that records changes to a file or set of files over time so that you can recall specific versions later. For the examples in this book, you will use software source code as the files being version controlled, though in reality you can do this with nearly any type of file on a computer.

#3 a manual detailing the house style of a particular publisher, publication, etc.

#4 Agile software development is a process that turns a vision for a business need into solutions. We use agile because it results in software that better supports our customer needs on a faster timeline.” The Agile movement is based on the overarching goal of building software more simply.

Explanation:

20 points not 40 i need the rest

5 0
3 years ago
Read 2 more answers
This program is to compute and write to a file the GPA for student scores read from an input file. The point values of the grade
VARVARA [1.3K]

Answer:

#Take input from the user

filename=input('Enter name of input file: ')

total_units=0#Total number of units for a student

total_score=0#Total score of a student

#Assign a score to each grade. I have reduced 0.33 for each grade. Change here if you need to

grade={'A':4.0,'A-':3.67,'B+':3.34,'B':3.01,'B-':2.68,'C+':2.35,'C':2.02,'C-':1.69,'D+':1.36,'D':1.03}

try:

with open(filename,"r") as input_file:#Open the file for input(reading)

output_file=open("GPA_output.txt","w") #Create and open GPA_output.txt if it doesn't exist for writing

for student_record in input_file:#read from input file

if("," in student_record):#if there is a , that means this is the student name

student_name=student_record.strip('\n')#Remove \n from student name

continue

else:

if(" " in student_record):#If a line contains spaces then its the student's grades for a course

student=student_record.split(" ")#Split to find the coursename, units and grade

#student[0]=coursename student[1]=units student[2]=grade

total_units+=int(student[1])#Calculate total units for 1 student

total_score+=int(student[1])*grade[student[2].strip('\n')]#Find the total score of a student

#grade[student[2]] will lookup for the score that we initialized earlier

#if student has a grade as A then this will look up as grade['A'] which will return 4

#Find the total score as product of this grade and units for this course

continue

else:

if(total_units>0):#Check if score has been calculated for a student earlier

print("in")

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

if(total_units>0):#Essential for the case when the file doesn't end with a new line(Check if total_units is not 0) which means a record is pending

#to be written to the file

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

input_file.close()#Close the input file

output_file.close()#Close the output file

except IOError as e:

print("Problem in Opening the required file")#Print a message if file cannot be opened

Explanation:

The program has been tested for all 3 scenarios mentioned i.e.

a. If the file ends without \n

b. If the file ends with 2 \n

c. If the file ends with 1 \n

PS: The Program will run irrespective of how it ends. Even if there are many \n at the end of file, the program will be fine.

3 0
3 years ago
write a function that counts the number of times the value of y occurs in the first n values in array x. y is an integer variabl
mixer [17]

Answer:

Following are the function of count:

void count(int y,int x[],int n) // function definition of count

{

int k,count=0;  // variable declaration

for(k=0;k<n;++k) // iterating over the loop

   {

   if(x[k]==y) //check the conndition number of times the value of y occurs

   {

   count++; // increment of count by 1

   }

   }

Explanation:

Following are the code in c language

#include <stdio.h> // header file  

void count(int y,int x[],int n) // function definition of count

{

int k,count=0;  // variable declaration

for(k=0;k<n;++k) // iterating over the loop

   {

   if(x[k]==y) //check the conndition number of times the value of y occurs

   {

   count++; // increment of count by 1

   }

   }

   printf(" the number of times the value of y occurs :%d",count); // display count value

   }

int main() // main method

{

   int x[100],y,n,k; // variable declarartion

   printf(" Enter the number of terms n :");

   scanf("%d",&n); // input the terms

   printf(" Enter the array x :");

   for(k=0;k<n;++k) // input array x

   {

   scanf("%d",&x[k]);

   }

   printf("Enter the value of y:");

   scanf("%d",&y);// input value y by user

    count(y,x,n); // calling function

   return 0;

}

In the given program we declared an array x ,variable  y and n respectively Input the array x ,y,n  by user after that we call the function count .In the count function we iterate the loop from o position to array length-1 and check the number of times the value of y occurs by using if statement  i.e  if(x[k]==y) if the condition of if block is true then we increment the count variable Otherwise not .Finally display the count variable which describe the number of count.

Output

Enter the number of terms n :5

1

2

2

56

5

Enter the value of y:2

the number of times the value of y occurs :2

Enter the number of terms n :5

1

2

3

56

5

Enter the value of y:26

the number of times the value of y occurs :0

7 0
3 years ago
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