Answer:
Explanation:
The following code is written in Java and creates the recursive function to find the longest common substring as requested.
static int lengthOfLongestSubsequence(String X, String Y) {
int m = X.length();
int n = Y.length();
if (m == 0 || n == 0) {
return 0;
}
if (X.charAt(m - 1) == Y.charAt(n - 1)) {
return 1 + lengthOfLongestSubsequence(X, Y);
} else {
return Math.max(lengthOfLongestSubsequence(X, Y),
lengthOfLongestSubsequence(X, Y));
}
}
Answer:
Copy and paste the needed information from text editor to clipboard then to the web browser.
Explanation:
The keylogging software is an application that can connect to the keyboard API through software APIs or could be kernel based or hypervisor based, JavaScript based etc, to capture keyboard events.
It records these events which makes this tool useful for attackers in networks. So long as the clipboard logging or screen logging does not accompany the keyboard loggers, data can be copied on clipboard and pasted to the target point.
L is a decidable language because the Turing machine accepts it.
L is a recognizable language if TM M recognizes it.
<h3>How do you know if a language is decidable?</h3>
A language is said to be decidable only when there seems to exists a Turing machine that is said to accepts it,
Here, it tends to halts on all inputs, and then it answers "Yes" on words that is seen in the language and says "No" on words that are not found in the language. The same scenario applies to recognizable language.
So, L is a decidable language because the Turing machine accepts it.
L is a recognizable language if TM M recognizes it.
Learn more about programming language from
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Answer:
B. 1 6 3
Explanation:
Given function definition for calc:
void calc (int a, int& b)
{
int c;
c = a + 2;
a = a * 3;
b = c + a;
}
Function invocation:
x = 1;
y = 2;
z = 3;
calc(x, y);
cout << x << " " << y << " " << z << endl;
- Since x is passed by value, its value remains 1.
- y is passed by reference to the function calc(x,y);
Tracing the function execution:
c=3
a=3
b=c+a = 6;
But b actually corresponds to y. So y=6 after function call.
- Since z is not involved in function call, its value remain 3.
So output: 1 6 3
